Answer:
2.951 × 10⁻⁵ M
Explanation:
Let's consider the acid reaction of hydrobromic acid according to Brönsted-Lowry acid-base theory.
HBr(aq) + H₂O(l) ⇒ Br⁻(aq) + H₃O⁺(aq)
Given the pH = 4.530, we can calculate the concentration of the hydronium ion using the following expression.
pH = -log [H₃O⁺]
[H₃O⁺] = antilog -pH = antilog -4.530 = 2.951 × 10⁻⁵ M
Answer:
Adding heat and increasing concentration are meant to cause an increase in the rate of a reaction
Explanation:
The rate of a chemical reaction is defined as the number of moles of reactants converted or products formed pee unit time. It is a measure of how quickly the reactants in a given reaction are used up to form products or how quickly products are formed from reactants.
Factors that affect the rate of a chemical reaction include:
1. Nature of reactants
2. Concentration/pressure (for gases) of reactants
3. Temperature of reaction mixture
4. Presence of light
5. Presence of a catalyst
The effect of increasing the concentration of reactants for a given chemical reaction is that the reaction rate will increase. This is so because, according to the collision theory of chemical reactions, the frequency of collision between reactant particles which results in a chemical reaction (effective collisions) will increase when the reactant particles are crowded together in a small space due to an increase in their concentration.
The effect of increasing temperature or adding heat to a reaction is that the reaction rate increases. When the heat is added to a reactant particles, the number of particles with energies greater than or equal to the activation energy (the minimum amount of energy that reactant particles must possess for effective collisions) increases. Also, the average speed of the reactant particles increases resulting in a greater frequency of collision. Hence, the rate of the chemical reaction increases.
Ne is the smallest
B is the biggest
It goes (smallest to largest) : Ne, F,C,B
<span>You must balance your equation correctly.
Here is your answer:
294gFeS2 x 1molFeS2/119.99 x 11mols O2/4mols FeS2--> 6.738mol O2
176gO2 x 1mol O2/32gO2 x 4mols FeS2/11mol FeS2--> 2mols FeS2
Now choose the molecule with the lowest amount (Limiting Reagent)
2molsFeS2 x 2molsFe2O3/4molsFeS2 x 159.7g
159.7g Fe2O3 grams produced.</span>
