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fomenos
3 years ago
11

In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)2(aq) 2 NaBr(aq) PbBr2(s) 2 NaNO3(aq)

The molar mass of NaBr is 102.9 grams and that of NaNO3 is 85 grams
Chemistry
1 answer:
lyudmila [28]3 years ago
7 0

Answer : The mass of NaBr is, 295.323 grams

Solution :

First we have to calculate the moles of NaNO_3.

\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}=\frac{244g}{85g/mole}=2.87moles

Now we have to calculate the moles of NaBr.

The balanced chemical reaction is,

Pb(NO_3)_2(aq)+2NaBr(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)

From the balanced reaction we conclude that

As, 2 moles of NaNO_3 react with 2 moles of NaBr

So, 2.87 moles of NaNO_3 react with 2.87 moles of NaBr

Now we have to calculate the mass of NaBr.

\text{Mass of }NaBr=\text{Moles of }NaBr\times \text{Molar mass of }NaBr

\text{Mass of }NaBr=(2.87mole)\times (102.9g/mole)=295.323g

Therefore, the mass mass of NaBr is, 295.323 grams

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The effect of increasing temperature or adding heat to a reaction is that the reaction rate increases. When the heat is added to a reactant particles, the number of particles with energies greater than or equal to the activation energy (the minimum amount of energy that reactant particles must possess for effective collisions) increases. Also, the average speed of the reactant particles increases resulting in a greater frequency of collision. Hence, the rate of the chemical reaction increases.

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