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inna [77]
3 years ago
8

Which of these shows a volume of 1.25 liters expressed in milliliters

Chemistry
2 answers:
GarryVolchara [31]3 years ago
7 0
The answer is 1.25 x 10^(3) mL
stellarik [79]3 years ago
3 0
I would use a conversation calculator
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True or False: Ionic bonding means atoms COMPLETELY GIVE AWAY OR TAKE their electrons from each other. *
ziro4ka [17]

Answer: The given statement is True.

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

Thus the given statement is True.

8 0
3 years ago
Four properties of water are listed.
kobusy [5.1K]

Answer:

It reacts with metals to form metal hydroxide and hydrogen gas. it s an chemical property and it decomposes to H2 and O2 is also another chemical property property. because in these reaction H2O has changed to something else hence are called chemical property.

Explanation:

4 0
2 years ago
Read 2 more answers
Atoms of two different elements must have different
kogti [31]

Answer:

C atomic number

Explanation:

As u go from left to right the atomic number changes

So C is the answer,

I took the test on edge and that was the answer

3 0
3 years ago
What is the volume, in liters, of 13.5 moles of a gas at STP? (STP = 273.15K, 1 atmosphere)
RideAnS [48]

Answer:

302.75 Liters

Explanation:

Given:

P = 1 atm

V = ?

n = 13.5 moles

R = 0.0821 atm x L / mole x K

T = 273.15 K

PV = nRT

(1) (V) = (13.5) (0.0821) (273.15)

V = 302.75 Liters

4 0
2 years ago
How much aluminum oxide are produced when 46.5g of Al react with 165.37g of MnO?
solong [7]

Aluminum oxide produced : = 79.152 g

<h3>Further explanation</h3>

Given

46.5g of Al

165.37g of MnO

Required

Aluminum oxide produced

Solution

Reaction

2 Al (s) + 3 MnO (s) → 3 Mn (s) + Al₂O₃ (s)

  • mol Al(Ar = 27 g/mol) :

mol = mass : Ar

mol = 46.5 : 27

mol = 1.722

  • mol MnO(Ar=71 g/mol) :

mol = 165.37 : 71

mol = 2.329

mol : coefficient ratio Al : MnO = 1.722/2 : 2.329/3 = 0.861 : 0.776

MnO as a limiting reactant(smaller ratio)

So mol Al₂O₃ based on MnO as a limiting reactant

From equation , mol Al₂O₃ :

= 1/3 x mol MnO

= 1/3 x 2.329

= 0.776

Mass Al₂O₃ (MW=102 g/mol) :

= 0.776 x 102

= 79.152 g

7 0
3 years ago
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