Question

The figure is made up of a cylinder and a sphere which has been cut in half. The radius of each half sphere is 6 mm. What is the volume of the composite figure? Use 3.14 for .Round to the nearest hundredth.

Answer 1

Answer: $2,034.72\ mm^3$

Step-by-step explanation:

The missing part is: "A cylinder and 2 half spheres. All have a radius of 6 millimeters. The cylinder has a height of 10 millimeters."

You need to use the following formulas to solve the exercise:

1. The volume of a cylinder can be calculated with:

$V_{c}=\pi r^2h$

Where "r" is the radius and "h" is the height.

2. The volume of a sphere can be calculated with:

$V_{s}=\frac{4}{3}\pi r^3$ Where "r" is the radius.

In this case you know that the cylinder and the sphere have a radius of 6 millimeters and the height of cylinder is 10 millimeters. Then, you can substitute values into each formula in order to find the volumes:

$Vc=(3.14)(6\ mm)^2(10\ mm)\\\\Vc=1,130.4\ mm^3\\\\\\Vs=\frac{4}{3}(3.14)(6\ mm)^3\\\\Vs=904.32\ mm^3$

Adding them, you get that the volume of the composite figure is:

$V_{CF}=1,130.4\ mm^3+904.32\ mm^3\\\\V_{CF}=2,034.72\ mm^3$