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a_sh-v [17]
3 years ago
9

Why are the parts of an atom that electrons occupy called electron clouds?

Physics
1 answer:
Anna [14]3 years ago
8 0

Because it's literally impossible to tell exactly where something that size is
located at any particular time.

And that's NOT because it's so small that we can't see it.  It's because any
material object behaves as if it's made of waves, and the smaller the object is,
the more the size of its waves get to be like the same size as the object. 
When you get down to things the size of subatomic particles, it doesn't make
sense any more to try and talk about where the particle actually "is", and we only
talk about the waves that define it, and how the waves all combine to become a
cloud of <em><u>probability</u></em> of where the particle is.

I know it sounds weird.  But that's the way it is.  Sorry.


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Answer:

Explanation:

Applied force, F = 18 N

Coefficient of static friction, μs = 0.4

Coefficient of kinetic friction, μs = 0.3

θ = 27°

Let N be the normal reaction of the wall acting on the block and m be the mass of block.

Resolve the components of force F.

As the block is in the horizontal equilibrium, so

F Cos 27° = N

N = 18 Cos 27° = 16.04 N

As the block does not slide so it means that the syatic friction force acting on the block balances the downwards forces acting on the block .

The force of static friction is μs x N = 0.4 x 16.04 = 6.42 N   .... (1)

The vertically downward force acting on the block is mg - F Sin 27°

                                                      = mg - 18 Sin 27° = mg - 8.172    ... (2)

Now by equating the forces from equation (1) and (2), we get

mg - 8.172 = 6.42

mg = 14.592

m x 9.8 = 14.592

m = 1.49 kg

Thus, the mass of block is 1.5 kg.  

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3 years ago
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A circuit has a current of 2.4 A. The voltage is increased to 4 times its original value, while the resistance stays the same. H
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Answer:

Resistance will become 4 times the previous value

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We have given current in the circuit i = 2.4 A

According to ohm's law current in the circuit is given by I=\frac{V}{R}

So 2.4=\frac{V}{R}............eqn 1

Now voltage is increased to 4 times so new voltage = 4 V

And current in the circuit is same as 2.4 A

We have to fond the resistance so that after increasing voltage current will be same

So 2.4=\frac{4V}{R_{unknown}}..........eqn 2

Dividing eqn 1 and 2

1=\frac{V}{R}\times \frac{R_{unkown}}{4V}

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