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kirill [66]
3 years ago
10

If the diameter of the smaller circle is 7 km and the width of the circular path is 0.5 km, find the area of the path. (Assume π

=3.14)

Mathematics
1 answer:
lana66690 [7]3 years ago
3 0

Answer:

12.1

Step-by-step explanation:

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Solve one of the two problems for x. The answers for both are the same. You are more than welcome to do both to check your answe
Fed [463]

Answer:

x = 49

Step-by-step explanation:

Let's solve for x in the first triangle by applying the leg rule.

Leg rule is given as: hypotenuse/leg = leg/part

Hypotenuse = x

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Part = 16

Plug in the values into the equation

x/28 = 28/16

Cross multiply

x*16 = 28*28

16x = 784

x = 784/16

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✔️Let's check our answer to see if we would get the same value of x for the other triangle. Apply the same leg rule.

Hypotenuse = x

Leg = 21

Part = 9

Thus:

x/21 = 21/9

Cross multiply

x*9 = 21*21

9x = 441

x = 441/9

x = 49

✔️We have the same value. Therefore, x = 49 is the correct answer.

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Help pls, it’s urgent!! ASAP! (Geometry)<br> “Compete the proof”
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1) \overline{AB} \cong \overline{CD}, \overline{AD} \cong \overline{CB}, \overline{AX} \perp \overline{BD}, \overline{CY} \perp\overline{BD} (given)

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3) \triangle ABD \cong \triangle ACDB (SSS)

4) \angle ADB \cong \angle CBY (CPCTC)

5) \angle CYB and \angle AXD are right angles (perpendicular lines form right angles)

6) \triangle CYB and \triangle AXD are right triangles (a triangle with a right angle is a right triangle)

7) \triangle AXD \cong \triangle CYB (HA)

8) \overline{AX} \cong \overline{CY} (CPCTC)

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2 years ago
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