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pantera1 [17]
3 years ago
12

HELP ASAP!

Physics
1 answer:
bonufazy [111]3 years ago
4 0

Answer:

The last significant figure is inherently uncertain because of the rounding off. The rounding-off uncertainty is usually half of the last figure's decimal-place value if no other uncertainty is expressed. As a rule of thumb results of measurements and calculations have a limited number of significant figures.

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v =  \lambda \times f
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D makes the most sense, but you just have to put two and two together and go with your gut feeling, first cross out the answers that don't make sense (A didnt make sense) and go from there! I hope the little bit above me helped you answer or decide :) Good luck!

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