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2 years ago

PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!

Physics

2 answers:

seraphim [82]2 years ago

5 0

Data points, I believe

morpeh [17]2 years ago

4 0

The answer is Data Point

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Which term describes a gap in the geologic record that occurs when sedimentary rocks cover an eroded surface?

Lemur [1.5K]

The term that describes a gap in the geologic record that occurs when sedimentary rocks cover an eroded surface is called unconformity.

Glad to help ya!! ;)

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2 years ago

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A 1-kg collar (located at point (2,2) from the origin) is pulled along a vertical, frictionless bar with a force of 10 N applied

faltersainse [42]

Answer:

The acceleration of the collar is 10 m/s²

Explanation:

Given;

mass of the collar, m = 1 kg

applied force on the bar, F = 10 N

The acceleration of the collar can be calculated by applying Newton's second law of motion;

F = ma

where;

F is the applied force

m is mass of the object

a is the acceleration

a = F / m

a = 10 / 1

a = 10 m/s²

Therefore, the acceleration of the collar is 10 m/s²

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2 years ago

Which property increases as an electromagnetic wave's energy decreases?

aleksklad [387]

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2 years ago

A characteristic in an experiment, such as how much food, how much space, how hot or how cold, is termed a ____________. (spelli

KATRIN_1 [288]

I think the term is a variable?

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In February 1955, a paratrooper fell 370 m from an airplane without being able to open his chute but happened to land in snow, s

nevsk [136]

a) 0.94 m

The work done by the snow to decelerate the paratrooper is equal to the change in kinetic energy of the man:

$W=\Delta K\\-F d = \frac{1}{2}mv^2 - \frac{1}{2}mu^2$

where:

$F=1.1 \cdot 10^5 N$ is the force applied by the snow

d is the displacement of the man in the snow, so it is the depth of the snow that stopped him

m = 68 kg is the man's mass

v = 0 is the final speed of the man

u = 55 m/s is the initial speed of the man (when it touches the ground)

and where the negative sign in the work is due to the fact that the force exerted by the snow on the man (upward) is opposite to the displacement of the man (downward)

Solving the equation for d, we find:

$d=\frac{1}{2F}mu^2 = \frac{(68 kg)(55 m/s)^2}{2(1.1\cdot 10^5 N)}=0.94 m$