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zaharov [31]
3 years ago
3

An unknown substance weighing 0.545g is placed into a bomb calorimeter with a heat capacity of 6.75 kJ/°C. When the sample is bu

rned completely, the temperature in the calorimeter rises from 23.3°C to 26.4°C.
Physics
1 answer:
Leokris [45]3 years ago
7 0

Answer:

heat generated by the reaction = 20.925 kJ

Explanation:

Assuming that the we asked heat generated by the reaction.

Q=C(T_2-T_1)

C= heat capacity = 6.75 KJ/°C

C= Cp×m

T_2= 26.4°C and T_1= 23.3°C

Q=6.75\times(26.4-23.3)

=20.925 kJ

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Anna [14]

Compute the work done on the table:

<em>W</em> = <em>Fd</em> = (320 N) (32 m) = 10,240 J

Divide this by the given time duration to get the power output:

<em>P</em> = <em>W</em>/∆<em>t</em> = (10,240 J) / (150 s) ≈ 63.3 W

3 0
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During a storm, the power went out at Bailey’s house. She had no electricity. What could she use as an alternate form of electri
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A battery operated lamp because battery's don't use your own electricity. They come with electricity already.
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A mass tied to the end of a 1.0 m-long string is swinging back and forth From its lowest point, the mass moves 4 cm to the right
ehidna [41]

Answer:

a) 2seconds.

Explanation:

The period of oscillation will not change . It will still be 2seconds although the length was doubled to 8cm.

This is because the amplitude does not change oscillation time.

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3 years ago
The velocity of a 640-kg auto is changed from 10.0 m/s to 44.0 m/s in 71.0 s by an external, constant force. (a) What is the res
n200080 [17]

Answer:

(a) <em>change in momentum of the car = 21760 kgm/s</em>

(b) <em>The magnitude of the force = 306.48 N</em>

Explanation:

<em>(a)</em>

<em>Change in momentum: </em><em>This is the product of mass and change in velocity. The unit of momentum is kgm/s. It can be expressed mathematically as,</em>

Change in momentum of the car = m(v-u)................. Equation 1

Where m = mass of the car, v = final velocity of the car, u = initial velocity of the car.

<em>Given: m = 640 kg, v = 44.0 m/s, u = 10.0 m/s.</em>

<em>Substituting these values into equation 1,</em>

<em>Change in momentum of the car = 640 (44-10)</em>

<em>change in momentum of the car = 640× 34</em>

<em>change in momentum of the car = 21760 kgm/s</em>

<em>change in momentum of the car = 21760 kgm/s</em>

<em>(b) Force:</em><em> Force of a body can be defined as the product of mass and its acceleration. It is measured in Newton (N). It can be expressed mathematically as,</em>

<em>Force = ma ................................ Equation 2</em>

<em> </em><em>    Or</em>

<em>Force = m(v-u)/t...................................... Equation 3</em>

<em>Where m = mass of the car, v = final velocity of the car, u = initial velocity of the car, a = acceleration of the car, t = time taken to change the velocity.</em>

<em>Given: m = 640 kg, u = 10.0 m/s v = 44 m/s, t = 71 s.</em>

<em>Substituting these values into equation 3</em>

<em>Force = 640(44-10)/71</em>

<em>Force = (640×34)/71</em>

<em>Force = 306.48 N</em>

<em>The magnitude of the force = 306.48 N</em>

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What happens to the speed of the particles if the temperature is increased
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