Answer: 1.653 × 10⁴ N/C
Explanation: Given Q= 3.6× 10^-6
we assume there is a charge q placed at a distance r = 1.4m exerting an electric field strength towards Q.
Hence
F = kQq/r²
K= 9× 10^9
Now recall that E = F/q (electric field due to that charge)
E =( kQq/r²)/q
E = kQ/r² substituting the values gave the answer above.
Answer:i think they do i dont understand your question it does not make sence
Explanation:
Answer:
27.6 m/s
5.64 s
Explanation:
Given:
Δy = 39 m
a = -9.8 m/s²
v = 0 m/s
Find: v₀
v² = v₀² + 2aΔy
(0 m/s)² = v₀² + 2 (-9.8 m/s²) (39 m)
v₀ = 27.6 m/s
Find: 2t
Δy = vt − ½ at²
(39 m) = (0 m/s) t − ½ (-9.8 m/s²) t²
t = 2.82 s
2t = 5.64 s
If the average velocity of the duck is zero, it means that the duck's location at the end of the time interval was the same as at the beginning of the interval, but says nothing about the duck's motion during that time.
For instance, the duck could have waddled around in a circle 20 times; as long as it wound up at the starting point, the displacement and average velocity is zero.