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Evgesh-ka [11]
3 years ago
12

Find the surface area of each figure. 6 yd 9 yd 4.1 yd

Mathematics
1 answer:
Tju [1.3M]3 years ago
5 0
To help find surface area you can add up all of the sides of the shape and multiply it by its height
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PLEASE HELP!!!!
saveliy_v [14]

Answer:

Hi there!

Your answers are:

1) 38^10

2) 20^3

Step-by-step explanation:

1) Theres a property that goes like this:

(x^m)^n = x^mn

When you do a power of a power, you multiply them together!

2) There's a property that looks like this:

x^ m / x^n = x^ m-n

When dividing exponents, subtract!

Hope this helps!

8 0
3 years ago
A triangle has vertices at R(1, 1), S(-2,-4), and T-3, -3). The triangle is transformed according to the rule Ro, 270 What the c
notsponge [240]

Answer:

Based on the situation above and the choices provided the he coordinates of S should be (2,4) while the coordinates of R is (-1, 1), and for the T it should be (–3, 3). I hope the answer will help.

3 0
3 years ago
What is this answer???
CaHeK987 [17]
-10 is the correct answer

3 0
3 years ago
3. Jillian reads a book at a steady pace. Which equation can describe Jillian’s progress using t for time in hours and C for cha
zaharov [31]

Answer:

You didnt include the graph oop

Step-by-step explanation:

3 0
3 years ago
4tan^2 x-8tanx+3=0 on interval [0,2pi]
Vadim26 [7]
\bf 4tan^2(x)+8tan(x)+3=0\qquad [0,2\pi ]
\\\\\\
\textit{since it's just a quadratic, we'll just factor it}
\\\\\\\
[2tan(x)+1][2tan(x)+3]=0\implies 
\begin{cases}
2tan(x)+1=0\\
\qquad tan(x)=-\frac{1}{2}\\
\qquad \measuredangle x=tan^{-1}\left( -\frac{1}{2} \right)\\
\qquad \measuredangle  x\approx 333.4^o, 153.4^o\\
2tan(x)+3=0\\
\qquad tan(x)=-\frac{3}{2}\\
\qquad \measuredangle x=tan^{-1}\left(-\frac{3}{2}  \right)\\
\qquad \measuredangle x\approx303.7^o, 123.7^o
\end{cases}
7 0
3 years ago
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