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Sindrei [870]
4 years ago
15

pppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppeeeeeeeeeeeeeeeerrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrffffffffffffffffffffffffffffffffffffffffl
Chemistry
2 answers:
Elza [17]4 years ago
7 0

Answer:

If the student studies more the grades are likely to go up

Explanation:

olasank [31]4 years ago
5 0

Answer:pppppppppppppppppppppppppppeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeerrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrfffffffffffffffffeeeeeeeeeeeeeeeeeeeccccccccccccccccccccccccccccccttttttttttttt

Explanation:

I made a word from per its perfect :)

You might be interested in
The bulk of nuclear waste is in the form of ______
Alina [70]

Answer:

The bulk of nuclear waste is in the form of <u>solid ceramic pellets</u>.

Explanation:

Nuclear fuel loaded into commercial reactors is generally in the form of solid ceramic pellets that are stacked into metal tubes and bundled together in fuel assemblies. After the atoms in the pellet split to release their energy, the pellets in tubes emerge as nuclear waste.

Pls, choose me as brainliest!

7 0
3 years ago
PLEASEEEE HELLPPP I CANT FAILL PLSS
sdas [7]
It’s the second won the air layer one
4 0
3 years ago
A cat that weighs 55 N sits on the top of a cat tree. It is 2 m above a 110N dog. How does the mass of the animals relate to the
Ivahew [28]

*sorry I can't give a full explanation.*

g = 9.8 m/s²

w = m*g

Weight of cat: 55 N = m*9.8

m = 5.61 kg

Weight of dog: 110 N = m*9.8

m = 11.22 kg

There is gravitational potential energy (GPE) acting on the cat since it's at the very top.

GPE of cat = m*g*h = 5.61*9.8*2 = 109.96 J

GPE of dog = m*g*h = 11.22*9.8*0 = 0 J (it's 0 m height because it's on the floor instead of in the tree)

But, if the dog was also 2 m up in the tree, its GPE would be 219.91 J.

As you can see, it's GRAVITATIONAL potential energy is bigger than the cat because it weighs more. Generally, if you were just trying to find the force which is w = m*g (since weight is a force), you would see that the bigger the mass, the bigger the force, and gravity stays the same.

Hope this helped

5 0
3 years ago
Cuando realizamos la "Estructura de
sergeinik [125]

Answer:

Electrones de valencia.

Explanation:

¡Hola!

En este caso, dado en química se conocen las estructuras de Lewis como representaciones gráficas de como los elementos están enlazados entre sí, debemos tener en cuenta que estos enlaces se forman entre los electrones de valenciam, los cuales son utilizados para su representación. Se sabe que los electrones de valencia son representados con puntos alrededor del elemento a través de puntos que se unen entre sí y son el número de electrons en la capa más externa de los elementos en cuestión; por ejemplo, cloro tiene 7 electrones de valencia, azufre tiene 6, hidrogeno 1, carbono 4 y así sucesivamente.

¡Saludos!

3 0
4 years ago
calculate the molarity of MgCl2 in the following solution: 5.34 g of MgCl2 is dissolved and diluted to 214 mL of solution.
anyanavicka [17]
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

\quad\hookrightarrow\quad \sf {0.262M }

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>

Molarity is used to measure the concentration of a solution , so it is also as molar concentration. It is denoted as M or Mol/L

<u>We </u><u>are </u><u>given </u><u>that </u><u>:</u>

  • Weight of \sf MgCl_{2} = 5.34g
  • Volume of solution = 214 ml , or 0.214 L

The molar mass of magnesium chloride ( \sf MgCl_{2} ) is 95.21 g / mol

We can calculate the molarity of the solution by dividing the number of moles of solute by volume of solvent in liter ,i.e:

\quad\longrightarrow\quad \sf  {M = \dfrac{n}{V} } ‎ㅤ‎ㅤ‎ㅤ⸻( 1 )

<em>Where,</em><em> </em>

  • M = molarity
  • n = number of moles
  • V = Volume

We can calculate the number of moles by dividing the actual mass by its molar mass ,i.e:

\quad\longrightarrow\quad \sf { n = \dfrac{w}{m}}‎ㅤ‎ㅤ‎ㅤ‎⸻ ( 2 )

<em>W</em><em>here,</em>

  • n = number of moles
  • m = molar mass
  • w = actual mass

<u>Therefore</u><u>,</u>

\implies\quad \tt {n =\dfrac{w}{m} }

\implies\quad \tt { n =\dfrac{5.35\: g}{95.21\: g /mol}}

\implies\quad{\pmb{ \tt {n = 0.056 mol}} }

<u>P</u><u>utting </u><u>the </u><u>values </u><u>in </u><u>equation </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u>

\implies\quad \tt {M=\dfrac{n}{V} }

\implies\quad \tt { M =\dfrac{0.056\:mol}{0.214\:L}}

\implies\quad\underline{\pmb{ \tt { M = 0.262 \:M }}}

7 0
2 years ago
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