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BaLLatris [955]
2 years ago
8

13. Why do you think the observed trend for atomic radii exists across a period? Down a​

Chemistry
1 answer:
Bezzdna [24]2 years ago
6 0
Here is a link to a website that explains these observed trends.

https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Book%3A_Introductory_Chemistry_(CK-12)/06%3A_The_Periodic_Table/6.15%3A_Periodic_Trends%3A_Atomic_Radius
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Which one of the following questions about animals called affairs, pictured above, is the scientific question?
tino4ka555 [31]

The answer is B...

because any of the others could have an opinion based answer but B will always be the same its a fact not opinion.

3 0
3 years ago
A disturbance in matter that carries energy from one place to another is called
siniylev [52]
The answer you're looking for is: a wave.
6 0
3 years ago
A. Calculate the empirical formula of a molecule with percent compositions: 55.3% potassium (K), 14.6% phosphorus (P), and 30.1%
Otrada [13]
The way you calculate the empirical formula is to firstly assume 100g. To find each elements moles you take each elements percentage listed, times it by one mole and divide it by its atomic mass. (ex: moles of K =55.3g x 1 mole/39.1g, therefore there is 1.41432225 moles of Potassium) Once you’ve completed this for every element you list each elements symbol beside it’s number of moles and divide by the smallest number because it can only go into its self once. After you’ve done this, you’ve found your empirical formula, which is the simplest whole number ratio of atoms in a compound. I’ve added an example of a empirical question I completed last semester :)

6 0
3 years ago
Read 2 more answers
Write a chemical equation for the following reaction. (Type your answer using format CH4 for CH4.) In water, iron(III) chloride
taurus [48]

Answer:

FeCl3(aq) -

3NaOH(aq) 0 Fe(OH)3(s) -

3NaCl(aq)

Explanation:

FeCl3(aq) -

3NaOH(aq) 0 Fe(OH)3(s) -

3NaCl(aq)

7 0
2 years ago
PLEASE HELP!!!! 20 MINS LEFT IM DYING PLS HELP
Zepler [3.9K]

Answer:

Kc = 0.20        

Explanation:

                  N₂O₄     ⇄    2NO₂

moles       5.3mol          2.3mol

Vol               5L                5L

Molarity    5.3/5M        2.3/5M

                = 1.06M     = 0.46M

Kc = [NO₂]²/[N₂O₄] =  (0.46)²/(1.06) = 0.1996 ≅ 0.20

6 0
3 years ago
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