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3 years ago

Eeeeeeeeeeeeeeeeeeeeeeeeeeeee

Chemistry

2 answers:

Alexandra [31]3 years ago

7 0

Answer:

1. Closest

2. Million

3. All

4. Sunlight

5. Heat

6. Are

7. Faster

8. Million billion

9. Protection

10. Moon

11. Never

12. Tiny

13. Living

14. Explosions

15. Solar

give the other person brainliest

have a good day :)

Explanation:

kolezko [41]3 years ago

4 0

1. Closest

2. Million

3. All

4. Sunlight

5. Heat

6. Are

7. Faster

8. Million billion

9. Protection

10. Moon

11. Never

12. Tiny

13. Living

14. Explosions

15. Solar

Have a nice day!

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One litre of hydrogen at STP weight 0.09gm of 2 litre of gas at STP weight 2.880gm. Calculate the vapour density and molecular w

expeople1 [14]

Answer:

we know, at STP ( standard temperature and pressure).

we know, volume of 1 mole of gas = 22.4L

weight of 1 Litre of hydrogen gas = 0.09g

so, weight of 22.4 litres of hydrogen gas = 22.4 × 0.09 = 2.016g ≈ 2g = molecular weight of hydrogen gas.

similarly,

weight of 2L of a gas = 2.88gm

so, weight of 22.4 L of the gas = 2.88 × 22.4/2 = 2.88 × 11.2 = 32.256g

hence, molecular weight of the gas = 32.256g

vapor density = molecular weight/2

= 32.256/2 = 16.128g

hence, vapor density of the gas is 16.128g.

Explanation:

4 0

2 years ago

What model is the basis for chemistry?<br> Group of answer choices

serg [7]

Answer:

bohrs atomic model

Explanation:

6 0

3 years ago

The balanced redox reactions for the sequential reduction of vanadium are given below.

Minchanka [31]

Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

Let us rewrite the given equations again.

$2VO_{2}^{+} (aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2VO^{2+}(aq)+Zn^{2+}+2H2O(l)$ $2VO^{2+}(aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2V^{3+} (aq)+Zn^{2+}+2H2O(l)$

$2V^{3+} (aq)+ Zn (s)\rightarrow 2V^{2+}(aq)+Zn^{2+}(aq)$

On adding above equations, we get the following combined equation.

$2VO_{2}^{+} (aq)+ 8H^{+} (aq) + 3Zn (s)\rightarrow 2V^{2+}(aq)+3Zn^{2+}(aq)+4H_{2}O(l)$

We have 12.1 mL of 0.033 M solution of VO₂⁺.

Let us find the moles of VO₂⁺ from this information.

$12.1 mL \times \frac{1L}{1000mL}\times \frac{0.033mol}{L}=0.0003993mol NO_{2}^{+}$

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.

Let us use this as a conversion factor to find the moles of Zn.

$0.0003993mol NO_{2}^{+}\times \frac{3mol Zn}{2molNO_{2}^{+}}=0.00059895mol Zn$

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.

Molar mass of Zn is 65.38 g/mol.

$0.00059895mol Zn\times \frac{65.38gZn}{1molZn}=0.0392gZn$

We need 0.0392 grams of Zn metal to completely reduce vanadium.

6 0

3 years ago

A mixture of 18 % 18% disinfectant solution is to be made from 16 % 16% and 23 % 23% disinfectant solutions. How much of each so

jeka94

Answer: 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

Explanation:

According to the dilution law,

$C_1V_1+C_2V_2=C_3V_3$

where,

$C_1$ = concentration of ist disinfectant solution = 16 %

$V_1$ = volume of pure acid solution = x gallons

$C_2$ = concentration of another disinfectant solution= 23%

$V_2$ = volume of another acid solution= (28-x) gallons

$C_3$ = concentration of resulting disinfectant solution = 18 %

$V_1$ = volume of resulting acid solution = 28 gallons

$16\times x+23\times (28-x)=18\times 28$

$x=20galllons$

(28-x) = (28-20) = 8 gallons

Thus 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

7 0

3 years ago

How many moles of water can be produced from the reaction of 28g of C3H8

Montano1993 [528]

2.55 moles H20 will be produced

7 0

3 years ago