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3 years ago

8

A line is drawn on a coordinate grid by the equation x = 5. Which of the following lines would represent a row perpendicular to

it?

1 answer:

DanielleElmas [232]3 years ago

7 0

Answer:

mmm

Step-by-step explanation:

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Help me please and thankyou

klemol [59]

Answer:

$\boxed{Option B}$

Step-by-step explanation:

=> $(-5*4)^3$

Using the distributive property

=> $(-5)^3*(4)^3$

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Step-by-step explanation:

The answer is no solution or a 0 with a line through it

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Vladimir79 [104]

Answer:

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The math team does practice drills that each last 1/6 hour. In February the team did practice drills for a total of 24 hours. Ho

kozerog [31]

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3 years ago

I am lost on what to do

Neko [114]

$\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
\\\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
-----------------------------\\\\
\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\
-----------------------------\\\\
\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}$

$\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}
\\\\\\
\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0$

4 0

4 years ago