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Kisachek [45]
4 years ago
12

If an atom has 34 protons and 40 neutrons, what is its atomic number?

Physics
2 answers:
Genrish500 [490]4 years ago
8 0

the atomic number of an atom is equal to the number of protons the atom has


the answer would be A. 34

Inga [223]4 years ago
5 0
The  atomic number is 34. (A)
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A bicyclist passing through a city accelerates after he passes the sign post marking the city limits at x=0. His acceleration is
Anni [7]

Answer:

A. 24 m, 14 m/s

B. 8.0 m

Explanation:

Given:

x₀ = 6.0 m

v₀ = 4.0 m/s

a = 5.0 m/s²

t = 2.0 s

A. Find: x and v

x = x₀ + v₀ t + ½ at²

x = (6.0 m) + (4.0 m/s) (2.0 s) + ½ (5.0 m/s²) (2.0 m/s)²

x = 24 m

v = at + v₀

v = (5.0 m/s²) (2.0 s) + (4.0 m/s)

v = 14 m/s

B. Find x when v = 6.0 m/s.

v² = v₀² + 2a (x − x₀)

(6.0 m/s)² = (4.0 m/s)² + 2 (5.0 m/s²) (x − 6.0 m)

x = 8.0 m

8 0
3 years ago
What direction does centripetal acceleration point?
Nesterboy [21]

Answer:

Inward

Explanation:

As the centripetal force acts upon an object moving in a circle at constant speed, the force always acts inward as the velocity of the object is directed tangent to the circle. This would mean that the force is always directed perpendicular to the direction that the object is being displaced. hope this helps :)

3 0
3 years ago
What is true of an object pulled inward in an electric field?
slava [35]

Answer:

option b

Explanation:

There is an object pulled inward in an electric field.

We have to find out of the four options given which is true.

a) The object has a neutral charge is false since when electric field pulls the object inward, there is a charge inside.

b) The object has a charge opposite that of the field, this option is correct since there will be an equal and opposite charge created by the object

c) The object has a negative charge will be correct only if the original charge was positive hence wrong

d) The object has a charge the same as that of the field is incorrect since this would be opposite the charge

So only option b is right

5 0
4 years ago
If the momentum of a 1000 kg car travelling at 10 m/s was transferred completely to a 20.0 kg traffic barrier, what would the fi
denis-greek [22]

Answer:

d. 500 m/s

Explanation:

Momentum: This is the product of the mass of a body to its velocity, The S.I unit of momentum is kgm/s.

Mathematically, momentum can be expressed as,

M = mv....................... equation 1

Where M = momentum, m = mass, v = velocity

deduced from the question,

Momentum of the car = momentum of the barrier.

MV = mv ............................. Equation 1

Where M = mass of the car, V = velocity of the car, m = mass of the barrier, v = velocity of the barrier.

making v the subject of the equation,

v = MV/m........................ Equation 2

Given: M = 1000 kg, V = 10 m/s, m = 20 kg.

Substitute into equation 2

v = 1000(10)/20

v = 500 m/s.

Hence the speed of the barrier = 500 m/s

The right option is d. 500 m/s

8 0
4 years ago
When a 4.20-kg object is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.00 cm. (a) If
mr_godi [17]

(a) 0.714 cm

First of all, we need to find the spring constant of the spring. This can be done by using Hooke's law:

F=kx

where

F is the force applied on the spring

k is the spring constant

x is the stretching of the spring

At the beginning, the force applied is the weight of the block of m = 4.20 kg hanging on the spring, therefore:

F=mg=(4.20)(9.8)=41.2 N

The stretching of the spring due to this force is

x = 2.00 cm = 0.02 m

Therefore, the spring constant is

k=\frac{F}{x}=\frac{41.2}{0.02}=2060 N/m

Now, a new object of 1.50 kg is hanging on the spring instead of the previous one. So, the weight of this object is

F=mg=(1.50)(9.8)=14.7 N

And so, the stretching of th spring in this case is

x=\frac{F}{k}=\frac{14.7}{2060}=0.00714 m = 0.714 cm

(b) 1.65 J

The work done on a spring is given by:

W=\frac{1}{2}kx^2

where

k is the spring constant

x is the stretching of the spring

In this situation,

k = 2060 N/m

x = 4.00 cm = 0.04 m is the stretching due to the external agent

So, the work done is

W=\frac{1}{2}(2060)(0.04)^2=1.65 J

8 0
4 years ago
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