Answer:
a). P = 688 atm
b). P = 1083.04 atm
c).Δ G = 16.188 J/mol
Explanation:
a). Fugacity 'f' can be calculated from the following equations :
where, P = pressure , Z = compressibility
Now, the virial equation is :
........(1)
Also, PV=ZRT for real gases .......(2)
∴ 
So from the fugacity equation ,
Putting the value of P = 500 atm in the above equation, we get,
f = 688 atm
b). Given f = 2P
∴ P = 1083.04 atm
c). dG = Vdp -S dt at constant temperature, dT = 0
Therefore, dG = V dp
![$\Delta G=R[\ln\frac{P_2}{P_1}+6.4 \times 10^{-4}(P_2-P_1)]$](https://tex.z-dn.net/?f=%24%5CDelta%20G%3DR%5B%5Cln%5Cfrac%7BP_2%7D%7BP_1%7D%2B6.4%20%5Ctimes%2010%5E%7B-4%7D%28P_2-P_1%29%5D%24)
![$\Delta G=8.314\times 298[\ln\frac{500}{1}+6.4 \times 10^{-4}(500-1)]$](https://tex.z-dn.net/?f=%24%5CDelta%20G%3D8.314%5Ctimes%20298%5B%5Cln%5Cfrac%7B500%7D%7B1%7D%2B6.4%20%5Ctimes%2010%5E%7B-4%7D%28500-1%29%5D%24)
Δ G = 16.188 J/mol
Answer:
A (Hypothesis) is scientific knowledge published through direct observation and remains constant scientific knowledge can change when scientists (generate hypothesis)
1. a sulfur-32 atom contains 16 protons, 16 neutrons, and 16 electrons. what is the mass (in grams) of a sulfur-32 atom?
The mass in grams of a sulfur-32 atom is 32.
That is how the isotopes are identified, showing the mass number of the isotope, which is the sum of protons and neutrons: 16 protons + 16 neutrons = 32 mass number = mass in grams of the isotope.
2. the mass of a neutron is 1.67 x 10-24 g. approximately what number of neutrons would equal a mass of one gram?
divide 1 gram by the number of neutrons per gram:
number of neutrons = 1 g / 1.67 * 10 ^ - 24 g / neutrons = 0.5998 * 10 ^ 24 neutrons = 5.998 * 10 ^23 neutrons.
39.25 g of water (H₂O)
Explanation:
We have the following chemical reaction:
2 H₂ + O₂ → 2 H₂O
Now we calculate the number of moles of each reactant:
number of moles = mass / molar weight
number of moles of H₂ = 14.8 / 2 = 7.4 moles
number of moles of O₂ = 34.8 / 32 = 1.09 moles
We see from the chemical reaction that 2 moles of H₂ will react with 1 mole of O₂ so 7.4 moles of H₂ will react with 3.7 moles of O₂ but we only have 1.09 moles of O₂ available. The O₂ will be the limiting reactant. Knowing this we devise the following reasoning:
if 1 moles of O₂ produces 2 moles of H₂O
then 1.09 moles of O₂ produces X moles of H₂O
X = (1.09 × 2) / 1 = 2.18 moles of H₂O
mass = number of moles × molar weight
mass of H₂O = 2.18 × 18 = 39.25 g
Learn more about:
limiting reactant
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Answer:
Explanation:
As an example, the following cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m) generates a cell voltage of +1.10 V under standard conditions. Calculate and enter delta G degree (with 3 sig figs) for this reaction in kJ/mol.
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m)
ΔG = ΔG° + RTInQ
Q = 1
ΔG = ΔG°
ΔG = =nFE°
n=no of electrons transfered.
E° = 1.1v
ΔG° = -2 * 96500 * 1.10
= -212300J
ΔG° =-212.3kJ/mol
<h3>Therefore, the ΔG° = -212.3kJ/mol</h3>
