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bixtya [17]
2 years ago
14

At what depth of lake water is the pressure equal to 201kpa?

Physics
1 answer:
Alex787 [66]2 years ago
5 0

Answer:

20m

Explanation:

Pressure = pgh

p = density of water 1000

kg/m^3

g = acceleration due to gravity 9.81 m/s^2

h is the depth of water

Pressure = 201 kPa = 201 x 10^3 Pa

201 x 10^3 = 1000 x 9.81 x h

201 x 10^3 = 9810h

h = 20.49 m

Approximately 20 m

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What is the measurement 6 centimeters equal to;
Lemur [1.5K]

Answer:

6 centimeter = 60 millimeter

Explanation:

1 meter = 100 centimeter

1 centimeter = 0.01 meter

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Hence, first option is wrong.

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4 0
3 years ago
An oxygen molecule is moving near the earth's surface. Another oxygen molecule is moving in the ionosphere (the uppermost part o
Elena-2011 [213]

Answer:

The ratio of the translational rms speed in the ionosphere to the translational rms near the earth's surface is \sqrt 3 :1

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v_{rms}=\sqrt{\dfrac{3kT}{m}}

So, v_{rms}\propto \dfrac{1}{\sqrt{T} }

When the temperature is three times greater.  

v'_{rms}=\dfrac{1}{3T}

The ratio of the translational rms speed in the ionosphere to the translational rms near the earth's surface is :

\dfrac{v_{rms}}{v'{rms}}=\dfrac{\sqrt 3}{1}

Hence, this is the required solution.

7 0
2 years ago
A series RLC circuit containing a resistance of 12Ω, an inductance of 0.15H and a capacitor of 100uF are connected in series acr
Artyom0805 [142]

Answer:

Impedance = 19.44ohms

Current = 5.14A

Power factor = 0.62

Explanation:

Impedance in an RLC AC circuit is defined as the total opposition to the flow of current in the resistor, inductor and capacitor.

Impedance Z = √R²+(Xl-Xc)²

Where R is the resistance = 12Ω

Inductance L = 0.15H

Capacitance C = 100uF = 100×10^-6F

Since Xl = 2πfL and Xc = 1/2πfC where f is the frequency.

Xl = 2π×50×0.15

Xl = 15πΩ

Xl = 47.12Ω

Xc = 1/2π×50×100×10^-6

Xc = 100/π Ω

Xc = 31.83Ω

Z =√12²+(47.12-31.83)²

Z = √144+233.78

Z = 19.44Ω

Impedance = 19.44ohms

To calculate the circuit current, we will use the expression V=IZ where V is the supply voltage = 100V

I = V/Z = 100/19.44

I = 5.14Amperes

To calculate the power factor,

Power factor = cos(theta) where;

theta = arctan(Xl-Xc)/R

theta = arctan(47.12-31.83)/12

theta = arctan(15.29/12)

theta = arctan1.27

theta = 51.78°

Power factor = cos51.78°

Power factor = 0.62

4 0
3 years ago
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