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3 years ago

At what depth of lake water is the pressure equal to 201kpa?

Physics

1 answer:

Alex787 [66]3 years ago

5 0

Answer:

20m

Explanation:

Pressure = pgh

p = density of water 1000

kg/m^3

g = acceleration due to gravity 9.81 m/s^2

h is the depth of water

Pressure = 201 kPa = 201 x 10^3 Pa

201 x 10^3 = 1000 x 9.81 x h

201 x 10^3 = 9810h

h = 20.49 m

Approximately 20 m

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Consider an ideal gas at 27.0 degrees Celsius and 1.00 atmosphere pressure. Imagine the molecules to be uniformly spaced, with e

My name is Ann [436]

To solve the exercise it is necessary to keep in mind the concepts about the ideal gas equation and the volume in the cube.

However, for this case the Boyle equation will not be used, but the one that corresponds to the Boltzmann equation for ideal gas, in this way it is understood that

$PV =NkT$

Where,

N = Number of molecules

k = Boltzmann constant

V = Volume

T = Temperature

P = Pressure

Our values are given as,

$N = 1$

$k = 1.38*10^{-23}J/K$

$T = 27\°C = 27\°C + 273 = 300K$

$P = 1atm = 101325Pa$

Rearrange the equation to find V we have,

$V = \frac{NkT}{P}$

$V = \frac{1(1.38*10^{-23})(300K)}{101325Pa}$

$V = 4.0858*10^{-26}m^3$

We know that length of a cube is given by

$V = L^3$

Therefore the Length would be given as,

$L = V^{1/3}$

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3 years ago

Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 7.1 g. Silver has 47 electrons

Assoli18 [71]

<u>Answer:</u> The number of electrons in given amount of silver are $1.87\times 10^{24}$

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of silver = 7.1 g

Molar mass of silver = 107.87 g/mol

Putting values in above equation, we get:

$\text{Moles of silver}=\frac{7.1g}{107.87g/mol}=0.066mol$

Number of electrons in 1 atom of silver = 47

According to mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of particles

So, 0.066 moles of silver will contain = - $(0.066\times 47\times 6.022\times 10^{23})=1.87\times 10^{24}$ number of electrons

Hence, the number of electrons in given amount of silver are $1.87\times 10^{24}$

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3 years ago

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lapo4ka [179]

Answer:

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3 years ago