Two protons are 1 × 10−10 m apart (about one atomic radius). Which interaction between two protons is stronger, the gravitationa
l attraction or the electric repulsion? Note that since both the gravitational and electric forces depend on the inverse square distance, this comparison holds true at all distances, not just at a distance of 1 × 10−10 m. Use the accurate values of G = 6.67 × 10−11 N·m2/kg2, proton mass of 1.67 × 10−27 kg, and electron mass of 9.11 × 10−31 kg.
a) First, calculate the electric force |Felec| = ___ N
b) Next, calculate the gravitational force |F grav| = ___ N
c) Calculate the ratio of the two forces |Felec|/|Fgrav| = ___
a) First, calculate the electric force |Felec| = ___ N
b) Next, calculate the gravitational force |F grav| = ___ N
c) Calculate the ratio of the two forces |Felec|/|Fgrav| = ___
1 answer:
You might be interested in
Answer:
I = 0.287 MR²
Explanation:
given,
height of the object = 3.5 m
initial velocity = 0 m/s
final velocity = 7.3 m/s
moment of inertia = ?
Using total conservation of mechanical energy
change in potential energy will be equal to change in KE (rotational) and KE(transnational)
PE = KE(transnational) + KE (rotational)
v = r ω
I = 0.287 MR²
Answer:
Radio waves have a wavelength between and
While,
X rays have a wavelength between 1m and 10km.
=> It is one of the condition of diffraction that the obstacle (coming in the way) must be comparable with the size of the wavelength.
=> This shows, that radio waves have a wavelength which is comparable with the size of buildings and can really easily diffract through it
=> While, X-rays are big enough to diffract through the wall.
So, if an X-ray technician stands behind a wall during the use of her machine, she will remain safe.