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Minchanka [31]
3 years ago
11

Insert the values from the question above for x, y, z, & n into KxFey(C204)z nH20 anod provide the correct coefficients to b

alance the following equation Fe(NH4 )2(SO4 )2.6H20+_H2C204+_K2C204+-H202 → K,Fey C204)z nH20+(NH4)2SO4+ H2S04+H20 (Hint: Remember H202, an oxidizing agent, was used in the synthesis, so you'll need to do a redox balance. Start with just the iron ions, balance the reaction, and then add the full formulas.)
Chemistry
1 answer:
vlada-n [284]3 years ago
8 0

Answer:

Explanation:

brainly is so gay i swear

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You add the protons and the nuetrons together i think
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Oksana_A [137]

Answer:

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Explanation:

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3.2 moles of H3PO4 to grams
Nimfa-mama [501]

Answer:

313, 6grams of H3PO4

Explanation:

We calculate the weight of 1 mol of H3PO4:

Weight 1 mol H3PO4= (Weight H)x3+ (Weight P)+(Weight 0)x4  =1gx3+31g+16gx4

Weight 1 mol H3PO4=98 g /mol

1 mol-----98 grams H3PO4

3,2mol----x= (3,2molx 98 grams H3PO4)/ 1mol=313,6 grams H3PO4

4 0
3 years ago
A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t
Leni [432]

Answer:

The reaction is endothermic.

Yes, absorbed

3.06x10¹kJ are absorbed

Explanation:

In the reaction:

2HgO(s) → 2Hg(l) + O₂(g) ΔH = 182kJ

As ΔH >0,

<em>The reaction is endothermic</em>

<em />

As the reaction is endothermic, when the reaction occurs,

<em>the heat is absorbed.</em>

<em></em>

Now, based on the equation, when 2 moles of HgO (Molar mass: 216.59g/mol), 182kJ are absorbed.

72.8g are:

72.8g * (1mol / 216.59g) = 0.3361 moles HgO.

that absorb:

0.3361 moles HgO * (182kJ / 2 moles) =

<h3>3.06x10¹kJ are absorbed</h3>
8 0
4 years ago
Iron is extracted from iron oxide in the Blast Furnace: Fe 2 O 3 + 3 CO → 2 Fe + 3 CO 2
arsen [322]

a. mass of iron = 69.92 g

b. percent yield = 93%

<h3>Further eplanation </h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

a.

Reaction

Fe₂O₃+3CO⇒2Fe+3CO₂

MW Fe₂O₃ :  159.69 g/mol

mol Fe₂O₃

\tt \dfrac{100}{159,69}=0.626

mol Fe₂O₃ : mol Fe = 1 : 2

mol Fe :

\tt \dfrac{2}{1}\times 0.626=1.252

mass of Fe(Ar=55.845 g/mol) :

\tt 1.252\times 55.845=69.92~g

b.

actual yield = 65 g

theoretical yield = 69.92 g

percent yield :

\tt =\dfrac{65}{69.92}=0.93=93\%

8 0
3 years ago
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