Explanation:
<h3>oxidation of Nitrogen in N2O3 is </h3><h2>+3</h2>
The true is that both substances will have 2 * 6.02* 10^23 = 12.04 * 10^23 particles (may be molucules or atoms(.
Also, the two moles of each substance will have different masses, because you have to multiply the number of moles of each substance by the respective molar mass (or atomic mass).
Data:
m (<span>Sample Mass) = ?
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (

)
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass

= 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:

Solving:



Answer:
By approximation would be letter
D) <span>
337.2 g</span>