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olganol [36]
2 years ago
7

1. Nene geese in Hawaii are endangered because of

Chemistry
1 answer:
lesya692 [45]2 years ago
8 0

Answer:

✔ habitat destruction

Explanation:

the 3 reasons are:

hunting

habitat loss

introduced predators

summed up its habitat destruction

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In a short paragraph, explain one thing you've learned from the course this year.
exis [7]

Answer:

ive learned about the chart , ive learned about the coolest chemicle reactions and how. the can change colors , ive also learned that chenistrey is all around us since the beginning of life ,and how liquid can turn solid

Explanation:

7 0
3 years ago
Write a net ionic equation to show how codeine, c18h21o3n, behaves as a base in water.
Lera25 [3.4K]

Actually, the ionic equation for this is a reversible equation since codeine is a weak base. Any weak base or weak acids do not completely dissociate which makes them a reversible process. The ionic equation for this case is:

<span>C18H21O3N  +  H3O+  </span><=> C18H21O3NH+ +  H2O 

7 0
3 years ago
How many moles are in 2.6 x 10 ^25 atoms of Li?​
Cerrena [4.2K]

Answer:

43 mole

Explanation:

Given data:

Number of atoms of Li = 2.6× 10²⁵ atoms

Number of moles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

2.6× 10²⁵ atoms × 1 mole / 6.022 × 10²³ atoms

0.43 × 10² mole

43 mole

5 0
3 years ago
A mixture contains only nacl and al2(so4)3. a 1.45 g sample of the mixture is dissolved in water, and an excess of naoh is added
Aleks [24]

When mixture of NaCl and Al₂(SO₄)₃ is allowed to react with excess NaOH, only Al₂(SO₄)₃ reacts with it and NaCl does not react with NaOH due to presence of common ion (Na⁺). On reaction gelatinous precipitate of aluminium hydroxide [Al(OH)₃] is produced.  The balanced chemical reaction is represented as-

Al₂(SO₄)₃ + 6NaOH → 2Al(OH)₃ + 3Na₂SO₄

On this reaction, 0.495 g = 0.495/78 moles =6.346 X 10⁻³ moles of Al(OH)₃.

As per balanced reaction, two moles of Al(OH)₃ is produced from one mole Al₂(SO₄)₃. So, 6.346 X 10⁻³ moles of Al(OH)₃ is produced from (6.346 X 10⁻³)/2 moles=3.173 X 10⁻³ moles of Al₂(SO₄)₃= 3.173 X 10⁻³ X 342 g of Al₂(SO₄)₃=1.085 g of Al₂(SO₄)₃.

So, mass percentage of Al₂(SO₄)₃ is= (amount of Al₂(SO₄)₃/total amount of mixture)X100 = \frac{1.085 X 100}{1.45} =74.8 %.

7 0
2 years ago
How many atoms of germanium<br> are present in a sample<br> containing 1.65 moles Ge?
otez555 [7]

Answer:

9.9363 x 10^23  atoms

Explanation:

1.65   x   Avagadro's Number

1.65 * 6.022 x 10^23 =

5 0
2 years ago
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