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AlexFokin [52]
3 years ago
12

Which of the following is a point slope equation of the line below (10,5)(2,2)

Mathematics
1 answer:
salantis [7]3 years ago
7 0
Point slope form follows the equation y-y₁=m(x-x₁), so we want it to look like that. Starting off with m, or the slope, we can find this using your two points with the formula \frac{ y_{1}  -y_{2} }{ x_{1} - x_{2} }. Note that y₁ and x₁ are from the same point, but it does not matter which point you designate to be point 1 and point 2. Thus, we can plug our numbers in - the x value comes first in the equation, and the y value comes second, so we have
\frac{5-2}{10-2} = \frac{3}{5} as our slope. Keeping in mind that it does not matter which point is point 1 and which point is point 2, we go back to  y-y₁=m(x-x₁) and plug a point in (I'll be using (10,5)). Note that x₁, m,  and y₁ need to be plugged in, but x and y stay that way so that you can plug x or y values into the formula to find where exactly it is on the line. Thus, we have our point slope equation to be y- 5= \frac{3}{5} (x-10)

Feel free to ask further questions!
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Peter baked 18 cookies. He gave 2/3 of the cookies to his friend. How many cookies did Peter give to his friend
andre [41]

Answer:

12

thStep-by-step explanation:

4 0
3 years ago
Read 2 more answers
the area of a rectangular volleyball court is 1800 square feet the courts length is twice it width write a system of equations t
Marianna [84]

Answer:

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

Step-by-step explanation:

Let

x ----> the length of rectangular volleyball court

y ---> the width of the rectangular volleyball court

we know that

The area of the rectangular volleyball court is equal to

A=xy

A=1,800\ ft^2

so

1,800=xy ----> equation A

x=2y -----> equation B

substitute equation B in equation A

1,800=(2y)y

1,800=2y^2

Solve for y

Simplify

900=y^2

take square root both sides

y=30\ ft

<em>Find the value of x</em>

x=2y

substitute the value of y

x=2(30)=60\ ft

therefore

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

7 0
3 years ago
Geometry Homework Question ​
mash [69]

Answer:

Distance is 8.485

Midpoint is (3,4)

Step-by-step explanation:

Use the points (-1,7) and (5,1)

Insert them into the equation and solve for D

D=\sqrt{x} ((5-(-1))^2 + (1-7)^2)\\D=\sqrt{x} ((6)^2 + (-6)^2)\\D=\sqrt{x} (36+36)\\D=\sqrt{x} (72)\\D=8.485

Insert points into second equation to find midpoint

(\frac{_1+5}{2} , \frac{7+1}{2}) \\(\frac{6}{2} ,\frac{8}{2} )\\(3,4)

7 0
3 years ago
Roger served 5/8 pound of cracker wich was 2/3 of the entire box what was the weight of the crackers originally in the box
horrorfan [7]
Answer:
original weight of the box = 15 / 16 pounds

Explanation:
Assume that the original amount in the box is x.
We are given that:
5/8 pounds represent 2/3 of the total amount (x).
This can be translated into the following equation:
(2/3) x = 5 / 8

Now, we will solve for x as follows:
(2/3) x = 5 / 8
Multiply both sides by 24 to get rid of the denominators as follows:
(2/3) x * 24 = (5 / 8) * 24
16 x = 15
Divide both sides by 16 to isolate the x as follows:
x = 15 / 16 pounds

Hope this helps :)

8 0
3 years ago
Can anyone help me with this?0​
sergeinik [125]

Answer:

C) (y - 1)(y - 5)

Step-by-step explanation:

Hi there!

First you separate your expression into groups.

(y^2-5y)(-1y+5)

Now we take the common multiple out of each.

y(y - 5)-1(y - 5)

Since we have two (y - 5)s, we can pull it out of the equation as its own common multiple.

After we do that, we are left with y - 1. (we got this from taking the common multiples out)

Now we are just left with (y - 5)(y - 1)

Hope this helped!

4 0
2 years ago
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