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USPshnik [31]
3 years ago
14

If sin theta = 4/5 and cos theta is in quadrant II, then cos theta and tan theta equal what?​

Mathematics
2 answers:
charle [14.2K]3 years ago
5 0

Answer:

In quadrant ll,

cos theta = -3/5

tan theta = -4/3

Step-by-step explanation:

In quadrant ll, only sin is positive, cos and tan are negative

sin theta = opposite/hypotenuse = 4/5

From Pythagoras theorem,

adjacent = sqrt(hyp^2 - opp^2) = sqrt(5^2 - 4^2) = sqrt(25 - 16) = sqrt(9) = 3

cos theta = adjacent/hypotenuse = -3/5

tan theta = opposite/adjacent = -4/3

larisa86 [58]3 years ago
3 0

Using the pythagorean identity, \cos^2{\theta} + \sin^2{\theta} = 1. Since \theta is in quadrant ||, we know that \cos{\theta} is negative. Solving the equation \cos^2{\theta} + (\frac{4}{5})^2 = 1 for \cos{\theta}, we get that \cos{\theta} = -\frac{3}{5}.

\tan{\theta} is equal to \frac{\sin{\theta}}{\cos{\theta}}, which is -\frac{4}{3}.

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