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photoshop1234 [79]
4 years ago
7

How will frost on the wings of an airplane affect takeoff performance?

Physics
1 answer:
san4es73 [151]4 years ago
8 0

Frost will disturb the smooth flow of air over the wing, unpleasantly distressing its lifting competence. In other words, this spoils the even flow of air over the wings, by this means decreasing lifting capability. Also, frost may avoid the airplane from becoming flying at normal departure speed.

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at a certain instant an object is moving to the right with speed 1.0 m/s and has a constant acceleration to the left of 1.0 m/s^
chubhunter [2.5K]
For this problem, you would use the equation v=u+at. In this case, u=1 v=0 (when the object is at rest) a=-1
v=u+at
0=1+(-1)t
t=1 second
3 0
4 years ago
How is power related to distance and time?
Monica [59]

There is no direct relationship between power
and either of those quantities.

4 0
4 years ago
A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
geniusboy [140]

The speed of the man and the chair after the book is thrown is 0.2 m/s.

The given parameters:

  • <em>mass of the book, m₁ = 2.1 kg</em>
  • <em>speed of the book, u₁ = 7.2 m/s</em>
  • <em>mass of the man, M = 70 kg</em>
  • <em>mass of the book, m = 9.2 kg</em>

<em />

The total mass of the man and the book is calculated as follows;

m₂ = 70 kg + 9.2 kg

m₂ = 79.2 kg

The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;

m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s

Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

8 0
3 years ago
Explain three ways visual aids help you study
Katen [24]
Visual aids are tools that help to make an issue or lesson clearer or easier to understand and know (pictures, models, charts, maps, videos, slides, real objects etc.). ... Visual aids are those devices which are used in classrooms to encourage students learning process and make it easier and interesting.
7 0
3 years ago
A point charge of +3 C is located at the origin of a coordinate system and a second point charge of -6 C is at x = 1.0 m. At w
Butoxors [25]

Answer:

The point at which the electrical potential is zero is x = +0.33 m.

Explanation:

By definition the electrical potential is:

V_{E} = \frac{K*q}{r}

Where:

K: is Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

r: is the distance

The point at which the electrical potential is zero can be calculated as follows:

V_{1} + V_{2} = 0

K(\frac{q_{1}}{r_{1}} + \frac{q_{2}}{r_{2}}) = 0    (1)

q₁ is the first charge = +3 mC

r₁ is the distance from the point to the first charge  

q₂ is the first charge = -6 mC

r₂ is the distance from the point to the second charge    

By replacing r₁ = 1 - r₂ into equation (1) we have:

K(\frac{q_{1}}{1 - r_{2}} + \frac{q_{2}}{r_{2}}) = 0   (2)

By solving equation (2) for r₂:

r_{2} = \frac{q_{1}}{q_{1} - q_{2}} = \frac{3 mC}{3 mC - (-6 mC)} = +0.33 m

                 

Therefore, the point at which the electrical potential is zero is x = +0.33 m.

I hope it helps you!  

8 0
3 years ago
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