For this problem, you would use the equation v=u+at. In this case, u=1 v=0 (when the object is at rest) a=-1
v=u+at
0=1+(-1)t
t=1 second
There is no direct relationship between power
and either of those quantities.
The speed of the man and the chair after the book is thrown is 0.2 m/s.
The given parameters:
- <em>mass of the book, m₁ = 2.1 kg</em>
- <em>speed of the book, u₁ = 7.2 m/s</em>
- <em>mass of the man, M = 70 kg</em>
- <em>mass of the book, m = 9.2 kg</em>
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The total mass of the man and the book is calculated as follows;
m₂ = 70 kg + 9.2 kg
m₂ = 79.2 kg
The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;

Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
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Answer:
The point at which the electrical potential is zero is x = +0.33 m.
Explanation:
By definition the electrical potential is:

Where:
K: is Coulomb's constant = 9x10⁹ N*m²/C²
q: is the charge
r: is the distance
The point at which the electrical potential is zero can be calculated as follows:

(1)
q₁ is the first charge = +3 mC
r₁ is the distance from the point to the first charge
q₂ is the first charge = -6 mC
r₂ is the distance from the point to the second charge
By replacing r₁ = 1 - r₂ into equation (1) we have:
(2)
By solving equation (2) for r₂:

Therefore, the point at which the electrical potential is zero is x = +0.33 m.
I hope it helps you!