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photoshop1234 [79]
3 years ago
7

How will frost on the wings of an airplane affect takeoff performance?

Physics
1 answer:
san4es73 [151]3 years ago
8 0

Frost will disturb the smooth flow of air over the wing, unpleasantly distressing its lifting competence. In other words, this spoils the even flow of air over the wings, by this means decreasing lifting capability. Also, frost may avoid the airplane from becoming flying at normal departure speed.

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Where should an object be placed in front of a concave mirror’s principal axis to form an image that is real, inverted, larger t
Charra [1.4K]
If the object is kept in between the principle axis and the focus but some what nearer to the focus then we will get the enlarge,erect,and real image.

7 0
3 years ago
Read 2 more answers
A lab cart flies off the end of a track on a lab table with a horizontal velocity of 2.08 m/s. If it lands 0.96 meters from the
lana [24]

Answer:

Option C. 1.2 m

Explanation:

The following data were obtained from the question:

horizontal velocity (u) = 2.08 m/s

Horizontal distance (s) = 0.96 m

Height (h) of the table =?

Next, we shall determine the time taken for the lab cart to get to the ground. This can be obtained as follow:

horizontal velocity (u) = 2.08 m/s

Horizontal distance (s) = 0.96 m

Time (t) =?

s = ut

0.96 = 2.08 × t

Divide both side by 2.08

t = 0.96 / 2.08

t = 0.5 s

Finally, we shall determine the height of the table as illustrated below:

Time (t) = 0.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) of the table =?

h = ½gt²

h = ½× 9.8 × 0.5²

h = 4.9 × 0.25

h = 1.2 m

Thus, the height of the table is 1.2 m

3 0
2 years ago
Can someone help me solve #6
MAVERICK [17]

So you know the speed of a wave, and speed is how much the wave moves per second. This wave travels 3x10^8 meters per second. So to find how for you traveled you need to know how many seconds the wave traveled for, 20 minutes is equal to 1200 seconds (times 20 minutes by 60). Then times the seconds by the speed (3x10^8 m/s)x(1200 s) = 3.6x10^11 meters

7 0
3 years ago
You are driving along a highway at 35.0 m/s when you hear the siren of a police car approaching you from behind and you perceive
Irina-Kira [14]

Answer:

Explanation:

In the first case you can use the expression for the Doppler effect when the source is getting closer and getting away

f'=f(\frac{v}{v-v_{s}})    (  1  )

f''=f(\frac{v}{v+v_s})   (  2 )

f' = perceived frequency when the source is getting closer

f'' = perceived frequency when the source is getting away

f = source frequency

v = relative speed

vs = sound speed

by dividing (1) and (2) you have

\frac{f'}{f''}=\frac{f}{f}\frac{\frac{v}{v-v_s}}{\frac{v}{v+v_s}}=\frac{v+v_s}{v-v_s}\\\\f'v-f'v_s=f''v+f''v_s\\\\v(f'-f'')=v_s(f''+f')\\\\v=v_s\frac{f''+f'}{f'-f''}=(340\frac{m}{s})\frac{1370Hz+1330Hz}{1370Hz-1330Hz}=67.5\frac{m}{s}

but this is the relative velocity, you have that

v=v_{sir}-v_{car}\\v_{sir}=v+v_{car}=67.5\frac{m}{s}+35\frac{m}{s}=102.5\frac{m}{s}

a. hence, the speed of the police car is 102.5m/s

6 0
3 years ago
Which shape below best describes the trajectory of a projectile? A. ellipse B. parabola C. spiral D. semicircle E. zigzag
jeka57 [31]
I believe the answer is B)

Hope this helps*

5 0
3 years ago
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