Net force also known as an Unbalanced force.
The Volume of a Cube with a side(s) of 11.4 cm is
<span>V = s^3 </span>
<span> V = (11.4)^3 cm^3 </span>
<span> V = 1481.544 cm^3 </span>
<span> V = 1482 cm^3</span>
<span>however the Surface Area of a cube is the combined area of all the sides </span>
<span> A = 6s^2 </span>
<span> A = 6(11.4)^2 cm^2 </span>
<span> A = 779.76 cm^2 </span>
Answer:
C) 50 m/s
Explanation:
With the given information we can calculate the acceleration using the force and mass of the box.
Newton's 2nd Law: F = ma
- 5 N = 1 kg * a
- a = 5 m/s²
List out known variables:
- v₀ = 0 m/s
- a = 5 m/s²
- v = ?
- Δx = 250 m
Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:
Substitute known values into the equation and solve for v.
- v² = (0)² + 2(5)(250)
- v² = 2500
- v = 50 m/s
The final velocity of the box is C) 50 m/s.
Answer:
Inertia = angular momentum / angular velocity
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