Flourine atom. Drag a valence electron from the left atom to the right atom. What happens?

In molecular oxygen (O=O) which atom is partially positive?

saveliy_v [14]

the oxygen atom

Explanation:

Water is a molecular compound consisting of polar molecules that have a bent shape. The oxygen atom acquires a partial negative charge while the hydrogen atom acquires a partial positive charge.

4 0

4 years ago

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You are on an alien planet where the names for substances and the units of measures are very unfamiliar.

neonofarm [45]

Given that in the alien planet the names of substances and the units in which they are measured in not familiar.

8 quibs of a substance called skvarnik is present.

The conversion factor between sleps and quibs is: 9 sleps = 13 quibs

Converting 8 quibs of skvarnick to sleps:

$8 quibs * \frac{9 sleps}{13 quips}= 5.54sleps$

5.54 when rounded to nearest tenth becomes 5.5.

So the correct answer would be 5.5

5 0

3 years ago

A photon with 2.3 eV of energy can eject an electron from potassium. What is the corresponding wavelength of this type of light?

Ira Lisetskai [31]

Answer:

$\lambda=540.16\ nm$

Explanation:

Given that:

The energy of the photon = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.60 × 10⁻¹⁹ J

So, Energy = $2.3\times 1.60\times 10^{-19}\ J=3.68\times 10^{-19}\ J$

Considering

$Energy=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength of the light being bombarded

Thus,

$3.68\times 10^{-19}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$\frac{3.68}{10^{19}}=\frac{19.878}{10^{26}\lambda}$

$3.68\times \:10^{26}\lambda=1.9878\times 10^{20}$

$\lambda=5.40163\times 10^{-7}\ m=540.16\times 10^{-9}\ m$

Also,

1 m = 10⁻⁹ nm

So,

$\lambda=540.16\ nm$

3 0

4 years ago

How many protons does the biggest element of the periodic table have?

AnnZ [28]

Cesium is the biggest, atom wise.It has 55 protons.

3 0

3 years ago

Perform the following for Part C of this lab:

kaheart [24]

Answer:

a. 0.0110 L

b. 0.0020 L

c. 0.011 mol

d. 5.5 M

e. 0.66 g

f. 33%

Explanation:

There is some info missing. I will use some values to show you the procedure and then you can replace them with your values.

Titrant (NaOH) concentration: 1.0 M

Vinegar volume: 2.0 mL

Initial buret reading (initial NaOH volume): 0.1 mL

Final buret reading (final NaOH volume): 11.1 mL

a. Calculate the volume of NaOH that was added to the vinegar. Convert this volume to liters. Show your work.

The volume of NaOH is the difference between the final and the initial buret reading.

11.1 mL - 0.1 mL = 11.0 mL × (1 L/1000 mL) = 0.0110 L

b. Convert the measured volume of vinegar to liters. Show your work.

2.0 mL × (1 L/1000 mL) = 0.0020 L

c. Calculate the moles of NaOH using the volume and molarity of NaOH. Show your work. moles = molarity x volume

moles = molarity × volume

moles = (1.0 mol/L) × 0.0110 L = 0.011 mol

d. Since the reaction ratio is 1:1, the moles of acetic acid in the vinegar is equal to the moles of NaOH reacted during the titration. Calculate the molarity of the acetic acid in the vinegar. Show your work. molarity = moles / volume

molarity = moles / volume

molarity = 0.011 mol/0.0020 L = 5.5 M

e. Calculate the grams of acetic acid in the vinegar. Show your work. mass = moles x molar mass (g/mol)

mass = moles × molar mass

mass = 0.011 mol × 60.05 g/mol = 0.66 g

f. Assuming that the density of vinegar is very close to 1.0 g/mL, the 2.0 mL sample of vinegar used in the titration should weigh 2.0 g. Use this to calculate the mass % of acetic acid in the vinegar sample. mass % = (mass acetic acid / mass vinegar) * 100%

mass % = (mass acetic acid / mass vinegar) * 100%

mass % = (0.66 g /2.0 g) * 100% = 33%

6 0

3 years ago

Flourine atom. Drag a valence electron from the left atom to the right atom. What happens? ​

Flourine atom. Drag a valence electron from the left atom to the right atom. What happens?