It would be 5.0 more in i did this
Nobody on here is going to write a entire cer for you
Answer:
12.5 g of Li are needed in order toproduce 0.60 moles of Li₃N
Explanation:
The reaction is:
6Li(s) + N₂(g) → 2Li₃N(s)
If nitrogen is in excess, the lithium is the limiting reactant.
Ratio is 2:6
2 moles of nitride were produced by 6 moles of Li
Then, 0.6 moles of nitride were produced by (0.6 .6)/ 2 = 1.8 moles of Li
Let's convert the moles to mass → 1.8 mol . 6.94 g/ 1mol = 12.5 g of Li
<u>Answer:</u>
<u>For A:</u> The
for the given reaction is ![4.0\times 10^1](https://tex.z-dn.net/?f=4.0%5Ctimes%2010%5E1)
<u>For B:</u> The
for the given reaction is 1642.
<u>Explanation:</u>
The given chemical reaction follows:
![2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)](https://tex.z-dn.net/?f=2NO%28g%29%2BCl_2%28g%29%5Crightleftharpoons%202NOCl%28g%29)
The expression of
for the above reaction follows:
![K_p=\frac{(p_{NOCl})^2}{(p_{NO})^2\times p_{Cl_2}}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%28p_%7BNOCl%7D%29%5E2%7D%7B%28p_%7BNO%7D%29%5E2%5Ctimes%20p_%7BCl_2%7D%7D)
We are given:
![p_{NOCl}=0.24 atm\\p_{NO}=9.10\times 10^{-2}atm=0.0910atm\\p_{Cl_2}=0.174atm](https://tex.z-dn.net/?f=p_%7BNOCl%7D%3D0.24%20atm%5C%5Cp_%7BNO%7D%3D9.10%5Ctimes%2010%5E%7B-2%7Datm%3D0.0910atm%5C%5Cp_%7BCl_2%7D%3D0.174atm)
Putting values in above equation, we get:
![K_p=\frac{(0.24)^2}{(0.0910)^2\times 0.174}\\\\K_p=4.0\times 10^1](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%280.24%29%5E2%7D%7B%280.0910%29%5E2%5Ctimes%200.174%7D%5C%5C%5C%5CK_p%3D4.0%5Ctimes%2010%5E1)
Hence, the
for the given reaction is ![4.0\times 10^1](https://tex.z-dn.net/?f=4.0%5Ctimes%2010%5E1)
Relation of
with
is given by the formula:
![K_p=K_c(RT)^{\Delta ng}](https://tex.z-dn.net/?f=K_p%3DK_c%28RT%29%5E%7B%5CDelta%20ng%7D)
where,
= equilibrium constant in terms of partial pressure = ![4.0\times 10^1](https://tex.z-dn.net/?f=4.0%5Ctimes%2010%5E1)
= equilibrium constant in terms of concentration = ?
R = Gas constant = ![0.0821\text{ L atm }mol^{-1}K^{-1}](https://tex.z-dn.net/?f=0.0821%5Ctext%7B%20L%20atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D)
T = temperature = 500 K
= change in number of moles of gas particles = ![n_{products}-n_{reactants}=2-3=-1](https://tex.z-dn.net/?f=n_%7Bproducts%7D-n_%7Breactants%7D%3D2-3%3D-1)
Putting values in above equation, we get:
![4.0\times 10^1=K_c\times (0.0821\times 500)^{-1}\\\\K_c=\frac{4.0\times 10^1}{(0.0821\times 500)^{-1})}=1642](https://tex.z-dn.net/?f=4.0%5Ctimes%2010%5E1%3DK_c%5Ctimes%20%280.0821%5Ctimes%20500%29%5E%7B-1%7D%5C%5C%5C%5CK_c%3D%5Cfrac%7B4.0%5Ctimes%2010%5E1%7D%7B%280.0821%5Ctimes%20500%29%5E%7B-1%7D%29%7D%3D1642)
Hence, the
for the given reaction is 1642.
Answer is: 2. can dissolve.
Ionic compounds separates into particles (ions) in water because of their ionic bond.
For example sodium chloride is ionic compound and strong electrolyte and dissociates in water on hydrated sodium cations and chlorine anions:
NaCl(aq) → Na⁺(aq) + Cl⁻(aq).
Ionic bond is the electrostatic attraction between oppositely charged ions (cations and anions).