Question

The pressure of a 1.0 liter balloon is at 1 atm at 293 K if you were to take the balloon into a freezer that is still at One ATM with a temperature of 263 K what would the new volume of the balloon be

Answer 1

Here we can say that number of moles as well as pressure will remain same for the balloon

so here we can say by ideal gas equation

$PV = nRT$

so here for constant pressure and constant number of moles we have

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

$\frac{1}{293} = \frac{V}{263}$

now by rearranging the equation we have

$V = \frac{263}{293}$

$V = 0.89 Liter$

so final volume will be 0.89 liter