Two forces Fa and Fb are applied to an object whose mass is 5.42 kg. slader The larger force is Fa. When both forces point due e ast, the object's acceleration has a magnitude of 0.651 m/s2. However, when Fa points due east and Fb points due west, the acceleration is 0.427 m/s2, due east. Find (a) the magnitude of Fa and (b) the magnitude of Fb.
2 answers:
Answer:
a)Fa=2.98 N
b)Fb=0.53 N
Explanation:
Given that
m= 5.42 kg
When force are acting in east direction:
So from second law of Newton's
Given that Fa is greater than Fb and acceleration is 0.651 .
Fa+Fb= m a
Fa+ Fb =5.42 x 0.651
Fa+ Fb =3.52 -------------1
Now when both acting in apposite direction
Given that Fa is greater than Fb and acceleration is 0.427 .
Fa-Fb= m a
Fa- Fb =5.42 x 0.427
Fa- Fb =2.44 -------------2
Now from equation 1 and 2
Add both equations
2 Fa = 5.96
Fa=2.98 N
From equation 1
Fb =3.52 -Fa
Fb=0.53 N
Answer:
Fa = 2.92N
Fb = 0.61N
Explanation:
According to the Newton's second law,
Force = mass × acceleration
Given two forces Fa and Fb applied on an object,
∑F = ma
If both forces points due east (+x direction)
∑F = Fa+Fb = ma
Fa+Fb = 5.42kg(0.651 m/s²)
Fa+Fb = 3.53... (1)
If Fa points due east (+x drn) and Fb points due west (-ve x direction)
∑F = Fa-Fb = 5.42(0.427)
∑F = Fa-Fb = 2.31... (2)
Solving equation 1 and 2 simultaneously to get the magnitude of the force Fa and Fb
Fa+Fb = 3.53... (1)
Fa-Fb = 2.31... (2)
Adding both equation:
2Fa = 3.53+2.31
2Fa = 5.84
Fa = 5.84/2
Fa = 2.92N
Substituting Fa = 2.92N into equation 2
Fa - Fb = 2.31
2.92 - Fb = 2.31
-Fb = 2.31 - 2.92
-Fb = -0.61
Fb = 0.61N
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