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aalyn [17]
3 years ago
11

Two forces Fa and Fb are applied to an object whose mass is 5.42 kg. slader The larger force is Fa. When both forces point due e

ast, the object's acceleration has a magnitude of 0.651 m/s2. However, when Fa points due east and Fb points due west, the acceleration is 0.427 m/s2, due east. Find (a) the magnitude of Fa and (b) the magnitude of Fb.
Physics
2 answers:
Mandarinka [93]3 years ago
6 0

Answer:

a)Fa=2.98 N

b)Fb=0.53  N

Explanation:

Given that

m= 5.42 kg

When force are acting in east direction:

So from second law of Newton's

Given that Fa is greater than Fb and acceleration is 0.651m/s^2.

Fa+Fb= m a

Fa+  Fb =5.42 x 0.651

Fa+ Fb =3.52                -------------1

Now when both acting in apposite direction

Given that Fa is greater than Fb and acceleration is 0.427m/s^2.

Fa-Fb= m a

Fa-  Fb =5.42 x 0.427

Fa- Fb =2.44                   -------------2

Now from equation 1 and 2

Add both equations

2 Fa = 5.96

Fa=2.98 N

From equation 1

Fb =3.52 -Fa

Fb=0.53  N

oee [108]3 years ago
5 0

Answer:

Fa = 2.92N

Fb = 0.61N

Explanation:

According to the Newton's second law,

Force = mass × acceleration

Given two forces Fa and Fb applied on an object,

∑F = ma

If both forces points due east (+x direction)

∑F = Fa+Fb = ma

Fa+Fb = 5.42kg(0.651 m/s²)

Fa+Fb = 3.53... (1)

If Fa points due east (+x drn) and Fb points due west (-ve x direction)

∑F = Fa-Fb = 5.42(0.427)

∑F = Fa-Fb = 2.31... (2)

Solving equation 1 and 2 simultaneously to get the magnitude of the force Fa and Fb

Fa+Fb = 3.53... (1)

Fa-Fb = 2.31... (2)

Adding both equation:

2Fa = 3.53+2.31

2Fa = 5.84

Fa = 5.84/2

Fa = 2.92N

Substituting Fa = 2.92N into equation 2

Fa - Fb = 2.31

2.92 - Fb = 2.31

-Fb = 2.31 - 2.92

-Fb = -0.61

Fb = 0.61N

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