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2 years ago

What is characteristic of a good insulator?

Physics

2 answers:

Aneli [31]2 years ago

7 0

Answer:

Explanation:

D, when electrons are not free to move.. the material is a good insulator

melamori03 [73]2 years ago

7 0

Answer:

D. Electrons are tightly bound to the nuclei.

Explanation:

In an insulator, the electrons of the outer most shell are bound with a very high electrostatic forces coming from the nucleus of each atom so electrons cannot flow around all atoms making up the material as in a conductor.

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A 120-V rms voltage at 60.0 Hz is applied across an inductor, a capacitor, and a resistor in series. If the rms value of the cur

klemol [59]

Answer:

The impedance of this circuit is 200 ohm.

Explanation:

Given that,

rms voltage = 120 v

Frequency = 60.0 Hz

rms current = 0.600 A

We need to calculate the impedance

Using formula of impedance

$Z=\dfrac{V_{rms}}{I_{rms}}$

Where, $V_{rms}$ = rms voltage

$I_{rms}$ = rms current

Z= impedance

Put the value into the formula

$Z=\dfrac{120}{0.600}$

$Z=200\ Omega$

Hence, The impedance of this circuit is 200 ohm.

8 0

3 years ago

You are making a telephone out of two aluminum cans and some string. You can choose between two types of string: a 2-m length of

Nataliya [291]

Answer:

C)You should use the thin cooking twine.

Explanation:

A)You can choose either because they are the same length and will produce the same wave speed.

B)You should use the heavy rope.

C)You should use the thin cooking twine.

The speed of wave in a string is given by the following formula:

| $v$ | = $\sqrt{\frac{F_T}{u} }$

Where | $v$ | = speed of wave, $F_T$ = tension in the string, and μ = mass per length of the string.

Even though the two strings have the same length, the μ (mass/length) for the heavy rope will be more than the that of a thin rope. Consequently, the $F_T$ :μ for the thin rope will be higher than that of the heavy rope and as such, gives a bigger | $v$ |.

Therefore, the thin rope should be used in order to get a faster wave speed in the telephone.

The correct option is C.

3 0

3 years ago

Which of the following displays has the highest hz frequency

Ganezh [65]

Answer:

Plasma

Explanation:

3 0

2 years ago

Help! I need to do this quickly!!!

umka2103 [35]

D is the answer. It is a firm statement.

8 0

2 years ago

(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is . Find the time i

a_sh-v [17]

Answer:

a) It took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves.

b) The minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds.

Explanation:

The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensitie. That radiation is formed by electromagnetic waves, which are transverse waves formed by an electric field and a magnetic field perpendicular to it.

The distribution of the radiation in the electromagnetic spectrum can also be given in wavelengths, but it is more frequent to work with it at frequencies:

Gamma rays

X-rays

Ultraviolet rays

Visible region

Infrared

Microwave

Radio waves.

Any radiation that belongs to electromagnetic spectrum has a speed in vacuum of $3x10^{8}m/s$ .

a) Find the time it took for his voice to reach the Earth via radio waves.

To know the time that took for Neil Armstrong's voice to reach the Earth via radio waves, the following equation can be used:

$c = \frac{d}{t}$ (1)

Where v is the speed of light, d is the distance and t is the time.

Notice that t can be isolated from equation 1.

$t = \frac{d}{c}$ (2)

The distance from the Earth to the Moon is $3.85x10^{8} m$ , therefore.

$t = \frac{3.85x10^{8} m}{3x10^{8}m/s}$

$t = 1.28s$

Hence, it took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves.

b) Determine the minimum time that will be required for a message from Mars to reach the Earth via radio waves.

The distance from the Earth to the Mars at its closest approach is $5.76x10^{10}m$ , therefore.

$t = \frac{5.76x10^{10}m}{3x10^{8}m/s}$

$t = 192s$

Hence, the minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds.

3 0

3 years ago