<span>Answer:
Well, let's start by finding the pressure due to the "extra" height of the mercury.
p = 1.36e4 kg/m³ · (0.105m - 0.05m) · 9.8m/s² = 7330 N/m² = 7330 Pa
The pressure at B is clearly p_b = p_atmos = p_gas + 7330 Pa
The pressure at A is p_a = p_gas = p_atmos - 7330 Pa
c) 1 atm = 101 325 Pa
Then p_gas = 101325 Pa - 7330 Pa = 93 995 Pa</span>
Answer:
warmed should be ur answer
Explanation:
hope it helps , pls mark me as brainliest
Answer:

Explanation:
For this exercise let's use hooke's law
F = - k x
where x is the displacement from the equilibrium position.
x =
if we have several springs in series, the total displacement is the sum of the displacement for each spring, F the external force applied to the springs
x_ {total} = ∑ x_i
we substitute
x_ {total} = ∑ -F / ki
F / k_ {eq} = -F
1 / k_ {eq} = ∑ 1 / k_i
if all the springs are the same
k_i = k



Theres 82 protons, 82 electrona and 125 neutrons . hope this helped