Answer:
The limiting reactant is acetic acid. All 125 g will react.
Explanation:
1. Assemble the information
We will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
Mᵣ: 60.05 78.00
3CH₃COO-H + Al(OH)₃ ⟶ (CH₃COO)₃Al + 3H₂O
Mass/g: 125 275
2. Calculate the moles of each reactant
3. Calculate the moles of (CH₃COO)₃Al from each reactant
Answer:
XY4Z2- dsp2
XY4Z- sp3d
XY5Z- sp3d2
XY2Z3- sp3d
XY2Z- sp2
XY3Z- sp3
XY2Z2- sp3
XY3Z2- sp3d
XY2 - sp
,XY3- sp2
XY4- sp3
,XY5- sp3d
XY6- sp3d2
Explanation:
In the answer box I have shown the hybridization patterns of the various arrangement of bond pairs and lone pairs.
Hybridization was put forward to explain the shapes of molecules under the valence bond theory. All molecules having the same hybridization pattern are based on the same geometry. Deviations from the expected geometry may arise due to the presence of lone pairs.
<u>Answer:</u> The for the reaction is -749.8 kJ.
<u>Explanation:</u>
Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.
The chemical reaction for the formation of follows:
The intermediate balanced chemical reaction are:
(1) ( × 2)
(2)
The expression for enthalpy of the reaction follows:
Putting values in above equation, we get:
Hence, the for the reaction is -749.8 kJ.
Answer : The new volume will be, 238.9 mL
Explanation :
Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Therefore, the new volume will be, 238.9 mL
Answer:
a. electrons are transferred from silver in AgCl (aq) to Cd (s)
Explanation:
In this reaction Ag is reduced:
While Cd is oxidized:
With those two semi-reactions we can see that there's a transfer of electrons from silver in AgCl(aq) to the solid cadmium.
For the record, given that Ag was reduced, Cd was the reducing agent. And because Cd was reduced, Ag was the oxidizing agent.