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Mice21 [21]
3 years ago
10

Halp balance plez (⊙◡⊙)

Chemistry
1 answer:
grandymaker [24]3 years ago
8 0

Answer: SnO2 + 2 H2 = Sn + 2 H2O

Explanation: I used a balance equation website. It's called WebQC if you want to check it out for future help.

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Can someone please answer this?
Amanda [17]

Answer:-

0.229 L

Explanation:-

Molar mass of AgBr = 107.87 x 1 + 79.9 x 1

=187.77 grams mol-1

Mass of AgBr = 150 grams

Number of moles of AgBr = 150 grams / 187.77 gram mol-1

= 0.8 mol

The balanced chemical equation is

NaBr (aq) + AgNO3 (aq)--> AgBr(s) + NaNO3(aq)

From the equation we can see that

1 mol of AgBr is produced from 1 mol of AgNO3.

∴ 0.8 mol of AgBr is produced from 1 x 0.8 / 1 = 0.8 mol of AgNO3.

Strength of AgNO3 = 3.5 M

Volume of AgNO3 required = Number of moles / strength

= 0.8 moles / 3.5

=0.229 L

8 0
4 years ago
Which base has the smallest base dissociation constant?
svp [43]

Answer:

D. ammonia, because the other three are the only three strong bases in the world (we do not need to memorize base dissociation constant for the test, we just need to know the three strong bases)

Explanation:

q u i z l e t

8 0
3 years ago
Why is it impossible to know the exact speed and position of an electron
spayn [35]
They are always changing speed and positions, and changing charges to move their shell and location
4 0
4 years ago
Think and infer:
galben [10]
Idk So sorry for that
5 0
4 years ago
Explain how the information given below could be used to determine the concentration of an unknown sample.
Vika [28.1K]

Answer:

See below

Explanation:Plot the known concentrations and adsorbance data.  Draw a best fit line through thwe points.  When the absorbance of a solution of unknown concentration (but same substance) is determined, find the concentration from the line at that absorption value.  See attached graph.

E.g., an sample of the same substance had an absorbance of 0.35.  Find that on the x scale and then determine the concentration that would be required to produce that level of absorbance.  0.483M in this case.

8 0
2 years ago
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