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3 years ago

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80 POINTS AND BRAINILEST REALLY NEEDED 1. Compare and contrast the volcanic activity at a mid-ocean ridge and at a subduction zo

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2.compare and contrast the volcanic activity at a mid-ocean ridge and at a subduction zone
3.how is plate tectonics involved in making mountains and making continents larger? What kind of plate boundary is involved in these processes?
4.is Texas near a subduction zones? jusify your answer using the terms plate boundary and plate tectonics

1 answer:

QveST [7]3 years ago

5 0

Answer:

i answered these already divergent yes and idk

Explanation:

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Plz help meee :((((((((((((((

Sveta_85 [38]

The answer is b. All you have to do is find the intercepts.

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3 years ago

Describe where each subatomic particle is found in an atom.

zysi [14]

The last column in the table lists the location of the three subatomic particles.Protons<span> and </span>neutrons<span> are located in the nucleus, a dense central core in the middle of the atom, while the electrons are located outside the nucleus.</span>

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3 years ago

Read 2 more answers

Compute the resistance in ohms of a silver block 10 cm long and 0.10 cm2 in cross-sectional area. ( = 1.63 x 10-6 ohm-cm)

Vedmedyk [2.9K]

The resistance of the silver block is given by
$R= \frac{\rho L}{A}$
where
$\rho=1.63 \cdot 10^{-6} \Omega \cdot cm$ is the silver resistivity
$L=10 cm$ is the length of the block
$A=0.10 cm^2$ is the cross-sectional area of the block

If we plug the data into the equation, we find the resistance of the silver block:
$R= \frac{(1.63 \cdot 10^{-6} \Omega \cdot cm)(10 cm)}{0.10 cm^2}=1.63 \cdot 10^{-4} \Omega$

3 0

4 years ago

A girl swings a 0.250 kg rock attached to a taut string in a circle around her head. Her hand holds the end of the string above

nydimaria [60]

Complete Question

The diagram of with this question is shown on the first uploaded image

Answer:

The value is $v = -6.543 \^ i + 9.47 \^ j + 0 \^ k$

Explanation:

From the question we are told that

The mass of the rock is $m = 0.250 \ kg$

The length of the string is $L = 0.75 \ m$

The angle the string makes horizontal is $\theta = 11.9^o$

The angle which the projection of the string onto the xy -plane makes with the positive x-axis is $\phi = 34.6^o$

The angular velocity of the rock is $w = 2.50 rev/s = 2.50 * 2\pi =15.7 \ rad/s$

Generally the radius of the circle made by the length of the string is mathematically represented as

$r = L cos(\theta )$

=> $r = 0.75 cos(11.9 )$

=> $r = 0.734 \ m$

Generally the resultant tangential velocity is mathematically represented as

$v__{R}} = w * r$

=> $v__{R}} = 15.7 *0.734$

=> $v__{R}} = 11.5 \ m/s$

Generally the tangential velocity along the x-axis is

$v_x = -v__{R}} * sin(\phi)$

=> $v_x =- 11.5 * sin(34.6)$

=> $v_x = -6.543 \ m/s$

The negative sign show that the velocity is directed toward the negative x-axis

Generally the tangential velocity along the y-axis is

$v_y = v__{R}} * cos(\phi)$

=> $v_y = 11.5 * cos(34.6)$

=> $v_y = 9.47 \ m/s$

Generally the tangential velocity along the y-axis is

$v_z = v__{R}} * cos(90)$

=> $v_z = 0 \ m/s$

Generally the tangential velocity at that instant is mathematically represented as

$v = -6.543 \^ i + 9.47 \^ j + 0 \^ k$

8 0

3 years ago

A spaceship starting from a resting position accelerates at a constant rate of 9.8 meters per second per second. How long and ho

Verizon [17]

Accelerating at 9.8 m/s² means that every second, the speed is 9.8 m/s faster than it was a second earlier. It's not important to the problem, but this number (9.8) happens to be the acceleration of gravity on Earth.

1% of the speed of light = (300,000,000 m/s) / 100 = 3,000,000 m/s .

Starting from zero speed, moving (9.8 m/s) faster every second,
how long does it take to reach 3,000,000 m/s ?

   (3,000,000 m/s) / (9.8 m/s²) = 306,122 seconds .
   (That's 5,102 minutes.)
(That's 85 hours.)
   (That's 3.54 days.)

Speed at the beginning . . . zero .
Speed at the end . . . 3,000,000 m/s
Average speed . . . . . 1,500,000 m/s

Distance = (average speed) x (time)

   = (1,500,000 m/s) x (306,122 sec) = 4.592 x 10¹¹ meters

   = 459 million kilometers

   That's like from Earth
      to    Sun
       to    Earth
          to Sun.

4 0

3 years ago