Question

Compute the resistance in ohms of a silver block 10 cm long and 0.10 cm2 in cross-sectional area. ( = 1.63 x 10-6 ohm-cm)

Answer 1

The resistance of the silver block is given by
$R= \frac{\rho L}{A}$
where
$\rho=1.63 \cdot 10^{-6} \Omega \cdot cm$ is the silver resistivity
$L=10 cm$ is the length of the block
$A=0.10 cm^2$ is the cross-sectional area of the block

If we plug the data into the equation, we find the resistance of the silver block:
$R= \frac{(1.63 \cdot 10^{-6} \Omega \cdot cm)(10 cm)}{0.10 cm^2}=1.63 \cdot 10^{-4} \Omega$