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Minchanka [31]
4 years ago
12

A 4.5 kg ball swings from a string in a vertical circle such that it has constant sum of kinetic and gravitational potential ene

rgy. Ignore any friction forces from the air or in the string. What is the difference in the tension between the lowest and highest points on the circle
Physics
1 answer:
pickupchik [31]4 years ago
5 0

Answer:

<em> 88.29 N</em>

Explanation:

mass of the ball = 4.5 kg

weight of the ball will be = mass x acceleration due to gravity(9.81 m/s^2)

weight W = 4.5 x 9.81 = 44.145 N

<em>centrifugal forces Tc act on the ball as it swings</em>.

At the top point of the vertical swing,

Tension on the rope = Tc - W.

At the bottom point of the vertical swing,

Tension on the rope = Tc + W

therefore,

difference in tension between these two points will be;

<em>Net tension = tension at bottom minus tension at the top</em>

= Tc + W - (Tc - W) = Tc + W -Tc + W

= 2W

imputing the value of the weight W, we have

2W = 2 x 44.145 =<em> 88.29 N</em>

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<u>Answer:</u>

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