Answer is
9.773m/s^2
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Given,
h=8848m
The value of sea level is 9.08m/s^2. So, Let g′ be the acceleration due to the gravity on Mount Everest.
g′=g(1 − 2h/h)
=9.8(1 - 6400000/17696)
=9.8(1 − 0.00276)
9.8×0.99724
=9.773m/s^2
Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s^2
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hope this helps :)
Otal energy= PEmax on the spring = KEmax of the oject
<span>Total Energy= KE+PE at v or x not maximum. </span>
<span>Using the second line </span>
<span>E= 3/4 E + PE </span>
<span>PE = 1/4 E </span>
<span>PEmax =E = 1/2 kA^2 </span>
<span>PE=E/4 = (1/2)kA^2 / 4= kA^2/8
</span>
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Answer:
Explanation:
m = Mass of each rod
L = Length of rod = Radius of ring
= Mass of ring
Moment of inertia of a spoke
For 8 spokes
Moment of inertia of ring
Total moment of inertia
The moment of inertia of the wheel through an axis through the center and perpendicular to the plane of the ring is .
