We know, Momentum is the product of mass and velocity. As velocity is equal, momentum of Truck will be greater as mass of Truck is greater than the scooter. As momentum is greater from truck side, it will transfer the same amount to the scooter, so it flies away
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The electric potential at the origin of the xy coordinate system is negative infinity
<h3>What is the electric field due to the 4.0 μC charge?</h3>
The electric field due to the 4.0 μC charge is E = kq/r² where
- k = electric constant = 9.0 × 10 Nm²/C²,
- q = 4.0 μC = 4.0 × 10 C and
- r = distance of charge from origin = x₁ - 0 = 2.0 m - 0 m = 2.0 m
<h3>What is the electric field due to the -4.0 μC charge?</h3>
The electric field due to the -4.0 μC charge is E = kq'/r² where
- k = electric constant = 9.0 × 10 Nm²/C²,
- q' = -4.0 μC = -4.0 × 10 C and
- r = distance of charge from origin = 0 - x₂ = 0 - (-2.0 m) = 0 m + 2.0 m = 2.0 m
Since both electric fields are equal in magnitude and directed along the negative x-axis, the net electric field at the origin is
E" = E + E'
= -2E
= -2kq/r²
<h3>What is the electric potential at the origin?</h3>
So, the electric potential at the origin is V = -∫₂⁰E".dr
= -∫₂⁰-2kq/r².dr
Since E and dr = dx are parallel and r = x, we have
= -∫₂⁰-2kqdxcos0/x²
= 2kq∫₂⁰dx/x²
= 2kq[-1/x]₂⁰
= -2kq[1/x]₂⁰
= -2kq[1/0 - 1/2]
= -2kq[∞ - 1/2]
= -2kq[∞]
= -∞
So, the electric potential at the origin of the xy coordinate system is negative infinity
Learn more about electric potential here:
brainly.com/question/26978411
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In contrast, extratropical cyclones have their strongest winds near the tropopause, which is about 8 miles above the surface. These differences are due to the tropical cyclone being “warm-core” in the troposphere, whereas extra-tropical cyclones are “warm-core” in the stratosphere and “cold-core” in the troposphere.
Answer:
The force exerted on the
is ![F = 2.25*10^{3} \ N](https://tex.z-dn.net/?f=F%20%3D%20%202.25%2A10%5E%7B3%7D%20%5C%20N)
Explanation:
From the question we are told that
The area is ![A = 2.34*10^{-3} \ m^2](https://tex.z-dn.net/?f=A%20%3D%20%202.34%2A10%5E%7B-3%7D%20%5C%20m%5E2)
The magnitude of charge placed on them is ![q = 7.07 * 10^{-7} C](https://tex.z-dn.net/?f=q%20%3D%20%207.07%20%2A%2010%5E%7B-7%7D%20C)
The charge placed between the plate is ![q_1 = 6.62 *10^{-5} C](https://tex.z-dn.net/?f=q_1%20%3D%206.62%20%2A10%5E%7B-5%7D%20C)
The electric field generated around the plate is mathematically represented as
![E = \frac{q}{A \epsilon_o}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7Bq%7D%7BA%20%5Cepsilon_o%7D)
Substituting values
![E = \frac{7.07*10^{-7}}{2.34*10^{-3} * 8.85 *10^{-12}}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7B7.07%2A10%5E%7B-7%7D%7D%7B2.34%2A10%5E%7B-3%7D%20%2A%208.85%20%2A10%5E%7B-12%7D%7D)
![E = 34*10^{6} \ V/m](https://tex.z-dn.net/?f=E%20%3D%2034%2A10%5E%7B6%7D%20%5C%20V%2Fm)
The force exerted the charge
is mathematically represented as
![F = q_1 * E](https://tex.z-dn.net/?f=F%20%3D%20%20q_1%20%2A%20E)
Substituting values
![F = 6.62 *10^{-5} * 34*10^{6}](https://tex.z-dn.net/?f=F%20%3D%20%206.62%20%2A10%5E%7B-5%7D%20%2A%2034%2A10%5E%7B6%7D)
![F = 2.25*10^{3} \ N](https://tex.z-dn.net/?f=F%20%3D%20%202.25%2A10%5E%7B3%7D%20%5C%20N)