Answer:
See the explanation below.
Explanation:
Circulation of blood and oxygen is possible in body when circulatory system work along with respiratory system. Through tranche air moves in and out from lungs, whereas, through pulmonary arteries and veins (both connected to heart) blood moves in and out from the lungs. As Lucille is facing problem in his respiratory and circulatory system hence, it is difficult for him to play soccer because under normal circumstances when there is increase in physical activity then muscle cell respire more as compare to when the body is on rest. So, with increase of physical activity there is also increase in the rate of breathing which result in more absorption of oxygen and more removal of carbon dioxide but if there is problem in respiratory and circulatory system, for example, infection in throat due to pollution,etc. then this normal process of breathing gets affected which sometime may prove fatal to the person.
I think it's Barium sulfate, the soild and percipitate
It depends, You have to have the length and the width of the crest wave.
Explanation:
itu Adalah ekseperiasi Yg sagat
mudah kita megola pelaharan dari mkt
kita igin melamar kerja Apa bila
kita visa mejawab nya degan benar
maka kina di terima jadi kariawan nya
kita terhadap bos harus patuh Dan
tidal pernah melakukan half Yg sgat Kevin
karen tidal boleh
itu lah Yg sya visa di sampaiksn pada kmu brenly
Answer:
(a) 23.946 kV
(b) -0.077 J
Explanation:
(a) The electric potential is given by the following formula:
(1)
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
q1 = q2 = 1.60*10^{-6}C
r1 and r2 are the distance from the charges to the point in which electric potential is evaluated.
Firs, you calculate the distance r1 and r2 by taking into account the position of the charges
Next, you replace the values of the parameters to calculate V:
(b) The potential electric energy is given by:
![U_T=U_{1,2}+U_{1,3}+U_{2,3}\\\\U_T=k\frac{q_1q_2}{r_{1,2}}+k\frac{q_1q_3}{r_{1,3}}+k\frac{q_2q_3}{r_{2,3}}\\\\r_{1,2}=2.00m\\\\r_{1,3}=1.20m\\\\r_{2,3}=1.20m\\\\U_T=(8.98*10^9)[\frac{(1.6*10^{-6})^2}{2.00m}+\frac{(1.6*10^{-6})(-3.70*10^{-6})}{1.20}+\frac{(1.6*10^{-6})(-3.70*10^{-6})}{1.20}]J\\\\U_T=-0.077J](https://tex.z-dn.net/?f=U_T%3DU_%7B1%2C2%7D%2BU_%7B1%2C3%7D%2BU_%7B2%2C3%7D%5C%5C%5C%5CU_T%3Dk%5Cfrac%7Bq_1q_2%7D%7Br_%7B1%2C2%7D%7D%2Bk%5Cfrac%7Bq_1q_3%7D%7Br_%7B1%2C3%7D%7D%2Bk%5Cfrac%7Bq_2q_3%7D%7Br_%7B2%2C3%7D%7D%5C%5C%5C%5Cr_%7B1%2C2%7D%3D2.00m%5C%5C%5C%5Cr_%7B1%2C3%7D%3D1.20m%5C%5C%5C%5Cr_%7B2%2C3%7D%3D1.20m%5C%5C%5C%5CU_T%3D%288.98%2A10%5E9%29%5B%5Cfrac%7B%281.6%2A10%5E%7B-6%7D%29%5E2%7D%7B2.00m%7D%2B%5Cfrac%7B%281.6%2A10%5E%7B-6%7D%29%28-3.70%2A10%5E%7B-6%7D%29%7D%7B1.20%7D%2B%5Cfrac%7B%281.6%2A10%5E%7B-6%7D%29%28-3.70%2A10%5E%7B-6%7D%29%7D%7B1.20%7D%5DJ%5C%5C%5C%5CU_T%3D-0.077J)
