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salantis [7]
4 years ago
6

Which example describes a nonrenewable resource?

Physics
2 answers:
BARSIC [14]4 years ago
7 0

Answer:

Refineries process oil, found in the Earth, and turn it into gasoline to be used by cars.

Explanation:

The first option describes Geothermal energy. Geothermal energy uses the heat of the Earth's crust as a heat source. It is a renewable resource.

Refineries use the oil extracted from the Earth to produce gasoline. This is a non renewable resource as the oil found in the Earth is of finite quantity and is being depleted faster than it is being replenished.

Solar panels use the sunlight to produce electricity. Sunlight is a renewable resource.

Windmill uses the power of moving air to generate electricity. Wind is a renewable resource.

In-s [12.5K]4 years ago
6 0
The refineries that use the oil to put in their cars as gasoline and then after a while the oil will disappear and go away and that's what a nonrenewable resource would be
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Why does matter increase in volume when it heats up?
ArbitrLikvidat [17]

Answer:All three states of matter (solid, liquid and gas) expand when heated. ... Heat causes the molecules to move faster, (heat energy is converted to kinetic energy ) which means that the volume of a gas increases more than the volume of a solid or liquid.

Explanation:well I tried lol she just copied and pasted faster than I could

8 0
3 years ago
slader the cross section of a 5-ft long trough is an isosceles trapezoid with a 2 foot lower base, a 3-foot upper base, and an a
Ostrovityanka [42]

Answer:

0.08 ft/min

Explanation:

To get the speed at witch the water raising at a given point we need to know the area it needs to fill at that point in the trough (the longitudinal section), which is given by the height at that point.

So we need to get the lenght of the sides for a height of 1 foot. Given the geometry of the trough, one side is the depth <em>d</em> and the other (lets call it <em>l</em>) is given by:

l=\frac{3-2}{2}\,ft+2\,ft\\l=2.5\,ft

since the difference between the upper and lower base is the increase in the base and we are only at halft the height.

Now we can calculate the longitudinal section <em>A</em> at that point:

A=d\times l\\A=5\,ft \times 2.5\, ft\\A=12.5\, ft^{2}

And the raising speed <em>v </em>of the water is given by:

v=\frac{q}{A}\\v=\frac{1\, \frac{ft^3}{min}}{12.5\, ft^2}\\v=0.08\, \frac{ft}{min}

where <em>q</em> is the water flow (1 cubic foot per minute).

7 0
3 years ago
A circular dartboard has a radius of 2 meters and a red circle in the center. Assume you hit the target at a random point. For w
Sati [7]

Answer:

1.549 m

Explanation:

Given:

The radius of the circular board, r = 2 m

The probability of hitting the red is given as 0.6

Now, this probability of hitting the red can be conclude as

0.6 = (Area of red)/ (Total area of the board)

Total area of the board = πr² = π × 2²

let the radius of the red area be R

thus, area of red circle, = πR²

on substituting the value of the area, we have

0.6 = (πR²)/ (π × 2²)

or

R² = 2.4

or

R = 1.549 m

Thus, the radius of the red circle is 1.549 m

3 0
3 years ago
You are a pirate working for dread pirate roberts. you are in charge of a cannon that exerts a force 10000 n on a cannon ball wh
KATRIN_1 [288]
<span>Answer: Let m = mass of cannon Then 10000 = ma a = 10000/m v^2 = u^2 + 2as v^2 = 0 + 2as 84^2 = 2(2.21)(10000/m) 84^2 m = 4.42(10000) m = 6.264172336 = 6.26 kg Part 2 Range = u^2sin(2x38)/g = 84^2sin(76)/9.8 = 698.6129229 = 698.6 m</span>
7 0
4 years ago
An experiment is conducted on a long straight wire of diameter d. A constant current is sent through the wire and the magnetic f
soldi70 [24.7K]

Answer:

D.

Explanation:

To solve the exercise it is necessary to apply the concepts related to the Magnetic Field described by Faraday.

The magnetic field is given by the equation:

B = \frac{\mu_0 I}{2\pi d}

Where,

\mu = Permeability constant

d = diameter

I = Current

For the given problem we have a change in the diameter, twice that of the initial experiment, therefore we define that:

B_1 = \frac{\mu_0 I}{2\pi d}

B_2 = \frac{\mu_0 I}{2\pi 2d}

The ratio of change between the two is given by:

\frac{B_2}{B_1} = \frac{\frac{\mu_0 I}{2\pi d}}{\frac{\mu_0 I}{2\pi 2d}}

\frac{B_2}{B_1} = \frac{d}{2d}

\frac{B_2}{B_1} = \frac{1}{2}

B_2 = B_1 \frac{1}{2}

Therefore the correct answer is D.

4 0
3 years ago
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