Answer:
See explaination
Explanation:
Reaction between p- toluidine and o- vaniline to form imine.This reaction does occur in the presence of a acidic source.
Here the -OH group in the o- vaniline is quite acidic so it acts a internal acidic catalyst. Hence the reaction occurred in the absence of any external acidic source.The reaction mechanism is given at the attached file.
please kindly see attachment.
Answer:
When ΔS > ΔH/ T, then the reaction will proceed forward
Explanation:
- The entity that determines the whether a reaction will occur on its own in the forward direction (Spontaneity or Feasibility) is Gibb's free energy.
- Gibb's free energy is the energy available to do work. It is denoted as 'G'. It cannot be easily measured. The change (ΔG) can only be measured. ΔG = ΔH - TΔS
when ΔG is positive, The reaction is not spontaneous (reaction will not occur on its own)
When ΔG is negative, The reaction is spontaneous (reaction will occur on its own)
When ΔG is zero, the reaction is in equilibrium
Option A and E are not correct. ΔH (Enthalpy) cannot determine spontaneity
Option C and D cannot alone determine spontaneity of reaction
For reaction to be spontaneous, TΔS > ΔH
Therefore, ΔS > ΔH/T
Answer: J
Explanation: when a object hits something it has a equal and opposite reaction pushing it back
<span>The answer is 2.519 × 10^4. Use the distributive property: a × x + b × x = (a + b) × x. If a = 4.659, b = 2.14, and x = 10^4, then 4.659 × 10^4 − 2.14 × 10^4 = (4.659 - 2.14) × 10^4. Now, subtract numbers in parenthesis: 4.659 × 10^4 − 2.14 × 10^4 = (4.659 - 2.14) × 10^4 = 2.519 × 10^4.Hope this helps. Let me know if you need additional help!</span>
Answer:
Explanation:
For a general equilibrium
aA +bB ⇔ cC + dD ,
the equilibrium constant is K = [C]^c [D]^d / [A]^a[B]^b.
Our reasoning here should be based on the fact that Q has the same expression as K, but is used when the system is not at equilibrium, and the system will react to make Q = K to attain it ( Le Chatelier´s principle ).
So with this in mind, lets answer this question.
1. False: Q can large or small but is not the value of the equilibrium constant, it will predict the side towards the equilibrium will shift to attain it.
2. False: Given the expression for the equilibrium constant, we know if K is small the concentrations of the reactants will be large compared to the equilibrium concentrations of the products.
3. False: when the value of K is large, the equilibrium concentrations of the products will be large and it will lie on the product side.
4. True: From our previous reasongs this is the true one.
5. False: If K is small, the equilibrium lies on the reactants side.
