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kenny6666 [7]
3 years ago
8

Solve for y: -9.6 - y + 4.4y = -1.5

Mathematics
1 answer:
Blababa [14]3 years ago
8 0

Answer:

y = 81/34

Step-by-step explanation:

-96+34y=-15

-96+34y+96=-15+96

34y=81

34y/34 = 81/34

y= 81/34

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ludmilkaskok [199]
No Its not Rational Number
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3 years ago
Which equations represent exponential growth? Which equations represent exponential decay? Drag the choices into the boxes to co
Norma-Jean [14]

Answer:

Exponential growth functions are:

A=20000(1.08)^{t}

A=40(3)^{t}

A=1700(1.07)^{t}

Exponential decay functions are:

A=80(\frac{1}{2})^{t}=80(0.5)^{t}

A=1600(0.8)^{t}

A=1700(0.93)^{t}

Step-by-step explanation:

Given:

An exponential function is of the form y=ab^{x}, where, a\ne 0.

Now, if a > 0 and b > 1, then the exponential function represent exponential growth.

If a > 0 and 0 < b < 1, then the exponential function represent exponential  decay.

Let us check each function now.

Option 1: A=20000(1.08)^{t}

Here, a = 20000, b = 1.08

As 1.08 > 1, the function is exponential growth.

Option 2: A=80(\frac{1}{2})^{t}=80(0.5)^{t}

Here, a = 80, b = 0.50

As 0.5 < 1, the function is exponential decay.

Option 3: A=1600(0.8)^{t}

Here, a = 1600, b = 0.8

As 0.8 < 1, the function is exponential decay.

Option 4: A=40(3)^{t}

Here, a = 40, b = 3

As 3 > 1, the function is exponential growth.

Option 5: A=1700(1.07)^{t}

Here, a = 1700, b = 1.07

As 1.07 > 1, the function is exponential growth.

Option 6: A=1700(0.93)^{t}

Here, a = 1700, b = 0.93

As 0.93 < 1, the function is exponential decay.

5 0
3 years ago
Help please I’ll mark you brainliest!!
worty [1.4K]

Answer:

35 ft

Step-by-step explanation:

Sorry this took me so long, I am 99% sure it is right though

I hope this helps :)

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3 years ago
The product of 4 and twice a number is 60
fredd [130]

Answer: I think the answer would be 4+2n=60.. might be wrong though

Step-by-step explanation:

6 0
3 years ago
Please Help!!! DUE NOW!
Alexxandr [17]

<em>Answer</em><em>:</em><em> </em><em>3</em><em>7</em>

<em>Step</em><em> </em><em>by</em><em> </em><em>step</em><em> </em><em>explanation</em><em>:</em>

<em>y</em><em>+</em><em>2</em><em>9</em><em>+</em><em>4</em><em>0</em><em>+</em><em>2</em><em>y</em><em>=</em><em>1</em><em>8</em><em>0</em><em>°</em><em>(</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>angle</em><em> </em><em>in</em><em> </em><em>stra</em><em>ight</em><em> </em><em>line</em><em>)</em>

<em>or</em><em>,</em><em> </em><em>y</em><em>+</em><em>2</em><em>y</em><em>+</em><em>2</em><em>9</em><em>+</em><em>4</em><em>0</em><em>=</em><em>1</em><em>8</em><em>0</em><em>°</em>

<em>or</em><em>,</em><em>3</em><em>y</em><em>+</em><em>6</em><em>9</em><em>=</em><em>1</em><em>8</em><em>0</em>

<em>or</em><em>,</em><em>3</em><em>y</em><em>=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>6</em><em>9</em>

<em>or</em><em>,</em><em>3</em><em>y</em><em>=</em><em>1</em><em>1</em><em>1</em>

<em>or</em><em>,</em><em>y</em><em>=</em><em>1</em><em>1</em><em>1</em><em>/</em><em>3</em>

<em>y</em><em>=</em><em>3</em><em>7</em>

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

5 0
3 years ago
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