Answer:
Newton's third law of motion states that whenever a first object exerts a force on a second object, the first object experiences a force equal in magnitude but opposite in direction to the force that it exerts. ... Newton's third law is useful for figuring out which forces are external to a system.
Explanation:
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Solution :
Given data :
Mass of the merry-go-round, m= 1640 kg
Radius of the merry-go-round, r = 7.50 m
Angular speed, 
rev/sec
rad/sec
= 5.89 rad/sec
Therefore, force required,
= 427126.9 N
Thus, the net work done for the acceleration is given by :
W = F x r
= 427126.9 x 7.5
= 3,203,451.75 J
Basic solutions are hydroxides therefore the answer is A ca(OH)2
F = ma, where m = mass in kg, a = acceleration in m/s², F = Force in Newton
F = 1 * 2
F = 2 N
Force needed is 2 Newtons.
Potential energy = (mass) x (gravity) x (height)
1 joule = (1,000 kg) x (9.8 m/s²) x (height)
Height = 1 joule / (9,800 newtons)
= 1/9800 meter
= 0.000102 meter
= 0.102 millimeter (rounded)
