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andre [41]
3 years ago
12

A guitarist finds that the pitch of one of her strings is slightly flat—the frequency is a bit too low. Should she increase or d

ecrease the tension of the string? Explain.
Physics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

The guitarist should increase the tension of the string.

Explanation:

The frequency of a vibrating string is determined by fn=(n/(2L))√T/μ. So if the tension in the string increased, the rate at which it vibrates (the frequency) will also increase.

Therefore it is advisable that she increase the tension of the string.

I hope it helps, please give brainliest if it does

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You want to determine whether the mass of an object attached to a parachute affects the time it takes to fall to the ground. In
hammer [34]

Answer:

The Answer is below!!

Explanation:

The larger the area of the parachute, the more air needs to be pushed out of the way, and so the slower it descends. the independent variable is the shape of the parachutes' canopies. The dependent variable is the drop speeds of the parachutes. How long does it take for the parachutes to reach the ground? Measure this using a stopwatch.

Hope I Helped!!

:)

5 0
2 years ago
A circular wire loop has a radius of 7.50 cm. a sinusoidal electromagnetic plane wave traveling in air passes throughthe loop, w
ExtremeBDS [4]

Intensity of electromagnetic wave is given as

I = 2[\frac{B_{rms}^2}{2\mu_0}\times c]

given that

I = 0.0275 W/m^2

0.0275 = \frac{B_{rms}^2}{\mu_0} \times c

here we know that

\mu_0 = 4\pi \times 10^{-7}

c = 3 \times 10^8 m/s

now we have

0.0275 = \frac{B_{rms}^2}{4 \pi \times 10^{-7}}(3 \times 10^8)

B_{rms} = 1.07 \times 10^{-8} T

now we will have

B_0 = \sqrt2 B_{rms}

B_0 = 1.52 \times 10^{-8} T

frequency of wave is given as

f = \frac{c}{\lambda}

f = \frac{3 \times 10^8}{6.90} = 4.35 \times 10^7 Hz

now the induced EMF is given as

EMF = B_0A2\pi f

EMF = 1.52 \times 10^{-8} \times \pi(0.075)^2 \times (2\pi \times 4.25 \times 10^7)

EMF = 0.0733 Volts

7 0
3 years ago
Read 2 more answers
a stone is thrown by a person from the top of the building, which is 200m tall. at the same time, another stone is thrown with v
solniwko [45]

Answer:

The time after which the two stones meet is tₓ = 4 s

Explanation:

Given data,

The height of the building, h = 200 m

The velocity of the stone thrown from foot of the building, U = 50 m/s

Using the II equation of motion

                             S = ut + ½ gt²

Let tₓ be the time where the two stones  meet and x be the distance covered from the top of the building

The equation for the stone dropped from top of the building becomes

                            x = 0 + ½ gtₓ²

The equation for the stone thrown from the base becomes

                S - x = U tₓ - ½ gtₓ²  (∵ the motion of the stone is in opposite direction)

Adding these two equations,

                      x + (S - x) = U tₓ

                               S = U tₓ

                               200 = 50 tₓ

∴                                  tₓ = 4 s

Hence, the time after which the two stones meet is tₓ = 4 s   

6 0
3 years ago
Which of the following has the most biomass?
Crazy boy [7]
Where are the questions so that I can deliver a more accurate answer. 
8 0
3 years ago
A fly travels along the x-axis. His starting point is x = 16 m and his ending point 15x = - 25 m. His flight lasts 4.0 seconds H
gogolik [260]

Explanation:

Starting position at x  = 16m

Ending position at x  = -25m

Time of flight  = 4s

Unknown:

Distance flown  = ?

Displacement  = ?

Speed  = ?

Velocity  = ?

Solution:

To find the distance flown, we should understand that the body is moving on the x - plane;  

  So distance  = 16 + 25  = 41m

Displacement is 41m to the left or -x axis

Speed is the distance divided by the time taken;

      Speed  = \frac{distance}{time}   = \frac{41}{4}   = 10.25m/s

Velocity is 10.25m/s along -x axis

5 0
2 years ago
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