Answer:
588 J
Explanation:
PE (potential energy) = (mass) x (gravity) x (height)
mass = 12 kg
gravity = 9.8m/s^2
height = 5 m
PE = (12) x (9.8) x (5) = 588 J (Joules)
Answer: 9*10^15 N
Force=kqq/r^2
F=[(9*10^9)(1)(1)]/.001^2=9.0*10^15
Answer: 482.8032 km per hr
Explanation: 300 * 1.609344 =
The strength of the electric field will be 215760 NC⁻¹. The concept of the electric field strength is used in the problem.
<h3>What is electric file strength?</h3>
The electric field strength is defined as the ratio of electric force and charge. Its unit is NC⁻¹.
The given data in the problem is;
E is the Electric Field Strength
k is the Colomb's constant = 8.99 x 10⁹ N.m²/C²
q is the magnitude of charge = 6 μC = 6 x 10⁻⁶ C
r is the distance = 0.5 m
The electric field strength is given by the formula;

Hence the strength of the electric field will be 215760 NC⁻¹.
To learn more about the electric field strength refer to the link;
brainly.com/question/4264413