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ehidna [41]
3 years ago
11

For each reaction, calculate how many moles of the barium product you will produce using stoichiometry and the balanced reaction

s.since there are two reactants, calculate the moles of product using each reactant, and then use the number of moles which is less) this comes from the limiting reactant).
Moles of Ba(NH2SO3)2.
Chemistry
1 answer:
ankoles [38]3 years ago
3 0

Answer:

Explanation:

given that

mass of Ba(NO3)2 = 1.40g

mass of NH2SO3H = 2.50 g

1)to determine the mole of  Ba(NO3)2

2) to determine the mass of all three product formed in the reaction

reaction

Ba(NO3)2 + 2NH2SO3H → Ba(NH2SO3)2 + 2HNO3

<u>Solution</u>

we calculate the molar mass of each species by using their atomic masses

BA = 137.33g/mol

N = 14g/mol

O= 16g/mol

H = 1g/mol

S = 32g/mol

calculation

Ba(NO3)2 = Ba + 2N + 6O

= 137.33 + 2X 14 + 6 X 16

= 261.33g/mol

NH2SO3H = N + 3H + S+ 3O

=14 + 3X1 + 32 + 3X 16

= 97g/mol

Ba(NH2SO3)2 = Ba + 2N + 4H +2S +6O

= 137.33 + 2 X 14 + 4 X1 + 2X32 + 6 X 16

= 329.33g/mol

HNO3 = H + n + 3O

= 1 + 14 + 3 X 16

= 63g/mol

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Which species acts exclusively as spectator ions in this reaction
adelina 88 [10]

Answer:

K^+ and NO3^-

Explanation:

In a balanced ionic equation, we usually see the species that react to yield the main product in the reaction.

Consider the reaction;

Pb(NO3)2(aq) +2 KI(aq) -------> PbI2(s) + 2KNO3(aq)

The main product in this reaction is PbI2. Hence the balanced ionic equation is;

Pb^2+(aq) + 2I^-(aq) ------> PbI2(s)

Notice that K^+ and NO3^- did not participate in this reaction. All ions that are part of the molecular equation but do not participate in the ionic reaction equation are called spectator ions. Hence K^+ and NO3^- are spectator ions in this reaction as can be seen clearly above.

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3 years ago
How many molecules are in 0.0740 mol NH3?
Mariana [72]

Number of molecules NH₃ = 4.45 x 10²²

<h3>Further explanation   </h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

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N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mol of NH₃ = n = 0.074

So the number of molecules :

\tt N=n\times No\\\\N=0.0740\times 6.02\times 10^{23}\\\\N=4.45\times 10^{22}

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A.) mass and distance.

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