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3 years ago

A student measures the mass of a sample as 9.64 g. Calculate the percentage error, given that the correct mass is 9.80 g.

Chemistry

1 answer:

rosijanka [135]3 years ago

5 0

Answer:

<h3>The answer is 1.63 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

actual mass = 9.80 g

error = 9.80 - 9.64 = 0.16

We have

$p(\%) = \frac{0.16}{9.80} \times 100 \\ = 1.632653061...$

We have the final answer as

Hope this helps you

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A marble is L 1.32 W 1.32 H 1.32, what is the volume? Show your work

cupoosta [38]

The volume of the marble is 2.3 cube units.

From the question given above, the following data were obtained:

Length (L) = 1.32

Width (W) = 1.32

Height (H) = 1.32

Volume (V) =?

The volume of the marble can be obtained as follow:

V = L × W × H

V = 1.32 × 1.32 × 1.32

V = 2.3 cube units

Thus, the volume of the marble is 2.3 cube units.

Learn more about volume:

brainly.com/question/20665757

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2 years ago

What is the molarity of the nitric acid solution if 20.5 mL of a 0.125 M lithium hydroxide solution are needed to titrate a 25.0

sveticcg [70]

Answer:: We're asked to find the molar concentration of the NaCl solution given some titration data.

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2 years ago

Magnesium metal burns in air to form a mixture of magnesium oxide (MgO, M = 40.31) and magnesium nitride (Mg3N2, M = 100.95). A

dedylja [7]

Answer:

26.95 %

Explanation:

Air contains the highest percentage of oxygen and nitrogen gases. Magnesium then combines with both of the gases:

$2 Mg (s) + O_2 (g)\rightarrow 2 MgO (s)$

$3 Mg (s) + N_2 (g)\rightarrow Mg_3N_2 (s)$

Firstly, find the total number of moles of magnesium metal:

$n_{Mg} = \frac{1.000 g}{24.305 g/mol} = 0.041144 mol$

Let's say that x mol react in the first reaction and y mol react in the second reaction. This means:

$x + y = 0.041144 mol$

According to stoichiometry, we form:

$n_{MgO} = x mol, n_{Mg_3N_2} = \frac{y}{3} mol$

Multiplying moles by the molar mass of each substance will yield mass. This means we form a total of:

$m_{MgO} = 40.31x g, m_{Mg_3N_2} = \frac{y}{3} 100.95 g =$

The total mass is given, so we have our second equation to solve:

$40.31x + 33.65y = 1.584$

We have two unknowns and two equations, we may then solve:

$x + y = 0.041144$

$40.31x + 33.65y = 1.584$

Express y from the first equation:

$y = 0.041144 - x$

Substitute into the second equation:

$40.31x + 33.65(0.04144 - x) = 1.584$

$40.31x + 1.39446 - 33.65x = 1.584$

$6.66x = 0.18954$

$x = 0.028459$

$y = 0.041144 - x = 0.012685$

Moles of nitride formed:

$n_{Mg_3N_2} = \frac{y}{3} = 0.0042282 mol$

Convert this to mass:

$m_{Mg_3N_2} = 0.0042282 mol\cdot 100.95 g/mol = 0.4268 g$

Find the percentage:

$\omega_{Mg_3N_2} = \frac{0.4268 g}{1.584 g}\cdot 100\% = 26.95 \%$

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There are 3 electrons in lithium : )

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