Answer:
u = 11.6 m/s
Explanation:
The end of a launch ramp is directed 63° above the horizontal. A skier attains a height of 10.9 m above the end of the ramp.
Maximum height, H = 10.9
Let v is the launch speed of the skier. The maximum height attained by the projectile is given by :
![H=\dfrac{u^2\ sin^2\theta}{g}](https://tex.z-dn.net/?f=H%3D%5Cdfrac%7Bu%5E2%5C%20sin%5E2%5Ctheta%7D%7Bg%7D)
![10.9=\dfrac{u^2\ sin^2(63)}{9.8}](https://tex.z-dn.net/?f=10.9%3D%5Cdfrac%7Bu%5E2%5C%20sin%5E2%2863%29%7D%7B9.8%7D)
u = 11.6 m/s
So, the launch speed of the skier is 11.6 m/s. Hence, this is the required solution.
Answer: i would do something that is really easy and i will do test 2 where there aint a word problems and i am going 2 put the work 2 where it is 2 there standard i aint going 2 do sum over there standards of science.
Explanation:
the weight of the balloon is .030 * 10 = 0.3 N
the weight of the gas of volume v is 0.54*10 N
The lifting force of a volume of v m³ of displaced air is 1.29v N
so, we need
1.29*10*v = 0.3 + 0.54*10*v
or
1.29v = 0.03+0.54v
Answer:
B
Explanation:
i had a test on this and got it correct
Answer:0kgm/s
Explanation:
Momentum before collision=momentum after collision
Since the momentum of the two blocks have positive sign, it means they are moving in thesame direction
Therefore we use the formula
Momentum (A)+momentum (B)=Momentum (A)+momentum (B)
25+35=60+momentum (B)
60=60+momentum (B)
Momentum (B)=60-60
Momentum (B)=0kgm/s