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3 years ago

Which triangle is similar to triangle PQR using the pieces of Right Triangles Similarity Theorem?

1 answer:

6 0

sorry po sorry popopojhbvb

Top left is you answer

7 0

3 years ago

Svetlanka [38]

We know a or b != 0

but a-b==0 so both are the same unknown number

b/a must = 1

a/b is equivalent to b/a as a/b=1 as well.

So the last answer choice.

7 0

3 years ago

MAVERICK [17]

Answer:

If you center the series at x=1

$T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)$

Where $R(x)$ is the error.

Step-by-step explanation:

From the information given we know that

$f(x) = e^{2x^2}$

$f'(x) = 4x e^{2x^2}$ (This comes from the chain rule )

$f^{(2)}(x) = 4e^{2x^2} (4x^2+1)$ (This comes from the chain rule and the product rule)

$f^{(3)}(x) = 16xe^{2x^2}(4x^2 + 3)$ (This comes from the chain rule and the product rule)

If you center the series at x=1 then

$T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)$

Where $R(x)$ is the error.

3 0

3 years ago

mariarad [96]

The answer would be 114. I did 3 times 38 and thats what i got. I hope it helps:D This is from your friendly Tolkien fan.

6 0

4 years ago

artcher [175]

Ok this is impossible you speak spanish

6 0

3 years ago