Answer:
<em>Good Luck!</em>
Explanation:
Force applied by first student (F1) = 80 N
Force applied by the second student (F2) = 40 N
Displacement (d) = 10 m
Work done by first student (W1) = F1d = 80*10 = 800 J
Work done by second student (W2) = F2d = 40*10 = 400 J
Hence, the work done by the pushing student is 800 J and that by pulling student is
<h2> <u><em>400 J</em></u></h2>
<h2>
Option B is the correct answer.</h2>
Explanation:
Period of a spring mass arrangement is given by

where m is mass and k is spring constant.
So period of spring mass arrangement is independent of amplitude of motion.
Here amplitude changes from A to 2A.
Period for amplitude A is given by T.
Since period remains same for amplitude 2A also, the period is T.
Option B is the correct answer.
Answer:
The initial current, Io = 2.06×10^-4A
Explanation:
The I itial current ,Io of a circuit is given by:
Io = Vo/R
Where Vo = initial votage
R = resistance in ohms
Given:
Vo = 1.50V
R = 7290ohms
Io = 1.50/ 7290
Io = 2.06 ×10^-4A
Mosses, algae and flowering plants.