Two students try to move a heavy box. One pushes with the force of the 80N while the other pulls with a force of 40N in the same
1 answer:
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Answer:
The angular speed is 0.13 rev/s
Explanation:
From the formula
Where is the torque
is the moment of inertia
is the angular acceleration
But, the angular acceleration is given by
Where is the angular speed
and is time
Then, we can write that
Hence,
Now, to determine the angular speed, we first determine the Torque and the moment of inertia
.
Here, The torque is given by,
Where r is the radius
and F is the force
From the question
r = 3.00 m
F = 195 N
∴
Nm
For the moment of inertia,
The moment of inertia of the solid disk is given by
Where M is the mass and
R is the radius
∴
kgm²
From the question, time t = 2.05 s.
Putting the values into the equation,
rad/s
Now, we will convert from rad/s to rev/s. To do that, we will divide our answer by 2π
0.82 rad/s = 0.82/2π rev/s
= 0.13 rev/s
Hence, the angular speed is 0.13 rev/s,
Answer:
a = 2710m/s²
Explanation:
See attachment below.
